Question

我有一个CrawlSpider，代码如下。我通过tsocks使用Tor。当我开始我的蜘蛛，一切正常。使用init_request我可以在网站上登录并使用粘性cookie进行爬网。

但是当我停下来并恢复蜘蛛时问题就出现了。饼干变得不粘。

我给你Scrapy的回复。

=======================INIT_REQUEST================
2013-01-30 03:03:58+0300 [my] INFO: Spider opened
2013-01-30 03:03:58+0300 [my] INFO: Resuming crawl (675 requests scheduled)
............ And here crawling began

所以... def init_request中的callback = self.login_url没有被激活！

我认为scrapy引擎不希望在登录页面上再次发送请求。在恢复scrapy之前，我将login_page（我可以从网站上的每个页面登录）更改为不包含在restrict_xpaths中的不同内容。

结果是 - 恢复后我无法登录，之前的cookie丢失了。

有没有人有一些假设？

from scrapy.contrib.spiders import CrawlSpider,Rule
from scrapy.contrib.linkextractors.sgml import SgmlLinkExtractor
from scrapy.selector import HtmlXPathSelector
from scrapy.contrib.loader import XPathItemLoader
from scrapy.contrib.loader.processor import TakeFirst, MapCompose, Join, Identity
from beles_com_ua.items import Product
from scrapy.utils.response import get_base_url
from scrapy.utils.url import urljoin_rfc
from scrapy.utils.markup import remove_entities
from django.utils.html import strip_tags
from datetime import datetime
from scrapy import log
import re
from scrapy.http import Request, FormRequest

class ProductLoader(XPathItemLoader):
    .... some code is here ...


class MySpider(CrawlSpider):
    name = 'my'
    login_page = 'http://test.com/index.php?section=6&type=12'

    allowed_domains = ['test.com']
    start_urls = [
        'http://test.com/index.php?section=142',
    ]
    rules = (
        Rule(SgmlLinkExtractor(allow=('.',),restrict_xpaths=('...my xpath...')),callback='parse_item', follow=True),
    )
    def start_requests(self):
        return self.init_request()

    def init_request(self):
        print '=======================INIT_REQUEST================'
        return [Request(self.login_page, callback=self.login_url)]


    def login_url(self, response):
        print '=======================LOGIN======================='
        """Generate a login request."""
        return FormRequest.from_response(response,
            formdata={'login': 'mylogin', 'pswd': 'mypass'},
            callback=self.after_login)

    def after_login(self, response):
        print '=======================AFTER_LOGIN ...======================='
        if "images/info_enter.png" in response.body:
               print "==============Bad times :(==============="
        else:
           print "=========Successfully logged in.========="
           for url in self.start_urls:
            yield self.make_requests_from_url(url)

    def parse_item(self, response):
        hxs = HtmlXPathSelector(response)

        entry = hxs.select("//div[@class='price']/text()").extract()
        l = ProductLoader(Product(), hxs)
        if entry:
        name = hxs.select("//div[@class='header_box']/text()").extract()[0]
        l.add_value('name', name)
        ... some code is here ...
        return l.load_item()

Answer 1

init_request(self):仅在您从InitSpider而非CrawlSpider

继承时才可用

你需要像这样

从InitSpider继承你的蜘蛛

class WorkingSpider(InitSpider):

    login_page = 'http://www.example.org/login.php'
    def init_request(self):
        #"""This function is called before crawling starts."""
        return Request(url=self.login_page, callback=self.login)

但请记住，您无法在Rules中定义initSpider作为CrawlSpider中唯一可用的手动提取链接

恢复抓取后无法再次登录。恢复scrapy后饼干不粘

1 个答案: