要根据子元素的组合进行匹配的XPath查询

Question

给出以下XML Snippet

 <Events>
    <Event>
     <DateTime>22.09.2009 11:27:18</DateTime>
     <EventType>Download</EventType>
 </Event>

什么是XPath查询以返回今天创建的类型下载的所有事件？

Answer 1

/Events/Event[starts-with(DateTime, '22.09.2009') and EventType='Download']

由于我认为这是对上一个问题的跟进，您可能希望使用此代码段而不是SelectSingleNode来获取文件中的所有事件（如果可能有多个）：

foreach (XPathNavigator node in doc.CreateNavigator().Select(expression)) {
    // matching node found in document; will process all matching nodes
}

Answer 2

//Events/Event[contains(DateTime,'22.09.2009') and EventType='Download']

Answer 3

/Events/Event[substring(DateTime, 0, 10)='22.09.2009' and EventType='Download']