Question

如何使用jQuery或node.js的东西对json文件进行异步跨域请求（GET）？我有我的api，我只需要向文件发出请求

$.ajax({
    type: 'GET',
    url: "https://api.flightstats.com/flex/airports/rest/v1/json/active?appId=3a311b8b&appKey=5d67203e8afab7fe8d01e0debf177171",
    processData: true,
    data: {},
    dataType: "json"

});

结果

XMLHttpRequest
XMLHttpRequest cannot load https://api.flightstats.com/flex/airports/rest/v1/json/active?appId=3a311b8b&appKey=5d67203e8afab7fe8d01e0debf177171. Origin https://developer.flightstats.com is not allowed by Access-Control-Allow-Origin.

或

$.ajax({
    type: 'GET',
    url: "https://api.flightstats.com/flex/airports/rest/v1/json/active?appId=3a311b8b&appKey=5d67203e8afab7fe8d01e0debf177171?callback?",
    processData: true,
    data: {},
    dataType: "jsonp"        
});

结果

undefined

Answer 1

您的网址回调函数缺少=。这是正确的网址。然后尝试一下。

确保您没有在控制台中获得任何404错误。

检查控制台是否存在任何其他错误。

$.ajax({
    type: 'GET',
    url: "https://api.flightstats.com/flex/airports/rest/v1/json/active?appId=3a311b8b&appKey=5d67203e8afab7fe8d01e0debf177171?callback=?",
    processData: true,
    data: {},
    dataType: "jsonp",
    success:function(data){//do some thing with data},
    error:function(xhr, ajaxOptions, thrownError){//do with ajax errors}
});

Answer 2

试试这个：

$.ajax({
   type: 'GET',
   url: "https://api.flightstats.com/flex/airports/rest/v1/json/active?appId=3a311b8b&appKey=5d67203e8afab7fe8d01e0debf177171?callback=?",
   dataType: "jsonp",
   success:function(data){
       console.log(data);
   }      
});

如何使用get方法跨域jquery ajax响应？

2 个答案: