数组,如何仅显示“更改值”

时间:2009-09-22 10:11:36

标签: php foreach

假设我有一个包含日期和季节的数组,每天有一个条目。我想仅在季节值发生变化时打印数组行。

数组看起来像那样:

2009-10-28 00:00:00 (good season)  

2009-10-29 00:00:00 (good season) 

2009-10-30 00:00:00 (good season) 

2009-10-31 00:00:00 (good season) 

2009-11-01 00:00:00 (good season) 

2009-11-02 00:00:00 (bad season) 

2009-11-03 00:00:00 (bad season) 

2009-11-04 00:00:00 (bad season) 

2009-11-05 00:00:00 (bad season) 

3 个答案:

答案 0 :(得分:3)

循环,记录上一季:

$lastSeason = '';

foreach ($array as $date => $season)
{
    if ($season != $lastSeason)
        echo "Season changed on " . $date;

    $lastSeason = $season;
}

答案 1 :(得分:1)

存储最后一次迭代的状态,并将其与当前状态进行比较。如果它们不同,请打印该项目:

$last = null;
foreach ($array as $val) {
    if (preg_match('/^\d{4}-\d{2}\d{2} \d{2}:\d{2}:\d{2} \((good|bad) season\)$/', $val, $match)) {
        if ($last != $match[1]) {
            echo $val;
        }
        $last = $match[1];
    }
}

答案 2 :(得分:1)

假设您的数组是一个数组数组:

if(count($array) > 0) {
  $prev = $array[0]['season'];

  foreach ($array as $row) {
    if ($row['season'] != $prev) echo $row['date'];

    $prev = $row['season'];
  }
}