Question

我正在尝试获取过去7天的日期和总和（总计）。我正在尝试此代码并获取日期NULL和daily_sale 0.00

SELECT
  date,
  IFNULL( SUM( total ), 0 ) AS daily_sale
FROM sales
WHERE date BETWEEN NOW()
    AND DATE_SUB(NOW(), INTERVAL 7 DAY)

我注意到如何获取日期和每日总销售额。我希望得到结果

date       daily_sale    
2013-01-29 500.00
2013-01-28 500.00
2013-01-27 500.00
2013-01-26 500.00
...
2013-01-23 500.00

Answer 1

您可以尝试interval - 7 day：

SELECT  date, SUM(Coalese(total,0)) AS daily_sale
FROM yourtable
WHERE date BETWEEN NOW()  AND DATE_ADD(NOW(), INTERVAL -7 DAY)

不确定为什么between不起作用，请查看：

<强> SQLFIDDLE DEMO

select dates, sum(coalesce(daily_sale,0)) as total
from sales
where dates <= NOW()
and dates >= Date_add(Now(),interval - 7 day)
group by dates
;

|                          DATES | TOTAL |
------------------------------------------
| January, 23 2013 00:00:00+0000 |   500 |
| January, 24 2013 00:00:00+0000 |   500 |
| January, 27 2013 00:00:00+0000 |  1500 |
| January, 28 2013 00:00:00+0000 |  1000 |
| January, 29 2013 00:00:00+0000 |   500 |

Answer 2

来自MySQL BETWEEN...AND manual

expr BETWEEN min AND max

将其改为

    SELECT CURDATE( ),DATE_SUB( CURDATE() , INTERVAL 7 DAY ) AS weekEndDate, 
           `date` , SUM( COALESCE(`daily_sale`,0 ) ) AS weekly_sale
    FROM tbl_sale
    GROUP BY weekEndDate
    LIMIT 0 , 30

Working DEMO

注意：

日期是mysql预留关键字，因此将其封装在`
SUM的语法为SUM(column_name)，您的列名为 daily_sales

Answer 3

如果第一个日期表达式需要是较低的一个，正如@ diEcho的回答所示，那么你需要在表达式中使NOW()成为第二个术语，而不是第一个。

Answer 4

你应该在BETWEEN命令中使用最低日期，所以NOW（）必须在最后

SELECT
  date,
  IFNULL( SUM( total ), 0 ) AS daily_sale
FROM sales
WHERE date BETWEEN DATE_SUB(NOW(), INTERVAL 7 DAY) and NOW()

或者如果您每天都需要统计数据：

SELECT
  DATE(`date`),
  IFNULL( SUM( total ), 0 ) AS daily_sale
FROM sales
WHERE date BETWEEN DATE_SUB(NOW(), INTERVAL 7 DAY) and NOW()
group by DATE(`date`)

获得每日总销售额7天

4 个答案: