Question

我输入了一个数字（0-127），并希望显示带有该索引的ASCII字符。到目前为止，我只用自己的变量实现了这一点。有人可以用输入解释如何做到这一点吗？

我的代码：

import java.util.Scanner;

public class CharCode {
    public static void main (String [] args) {
        Scanner input = new Scanner(System.in);
        // obtain index
        System.out.print("Enter an ASCII code: ");
        String entry = input.next();
        // How do I get a char with the inputted ASCII index here?

        // I can do it with my own variable, but not with input:
        int i = 97;
        char c = (char) i; // c is now equal to 'a'
        System.out.println(c);
    }
}

Answer 1

我认为你想输入任何ASCII值，它将以char值显示。为此，您需要更改，因为您必须对用户输入执行这些操作。

int entry = input.nextInt(); // get the inputted number as integer
// and
char c = (char) entry;

或

对于您当前的实施

//entry has to be String of numbers otherwise it will throw NumberFormatException. char c = (char) (Integer.parseInt(entry)); // c will contain 'a'

如何接收索引并显示其ASCII字符？

1 个答案: