Question

我有三个表：产品，公司，类型。公司和类型与产品有一对多的关系。 [型号]

class Type extends BaseModel {
    public static $table = "type";
    public static $timestamps = true;

    public function products() {
      return $this->has_many('Products');
    }
}

[公司模式]

class Company extends BaseModel {
    public static $table = "company";
    public static $timestamps = true;

    public function products() {
        return $this->has_many('Products');
    }
}

[产品型号]

class Products extends BaseModel {
    public static $table = 'products';
    public static $timestamps = true;


    public function company() {
        return $this->belongs_to('Company');
    }

    public function type() {
        return $this->belongs_to('Type');
    }
}

在add_product路线中我有

$product = new Products($new_product); 
$company_id = $all_posts['company_id'];
$company = Company::find($company_id);
$company->products()->save($product);
$type_id = $all_posts['type'];
$type = Type::find($type_id);
$type->products()->save($product);

但是当我尝试将数据插入db时，我得到：

SQLSTATE[23000]: Integrity constraint violation: 1062 Duplicate entry '11' for key 'PRIMARY'

如何更新Products表中的type_id和company_id？

Answer 1

如果我没有错，你的product表应该有product_id和type_id列？只需指定这些值：

$new_product['company_id'] = $all_posts['company_id'];
$new_product['type_id'] = $all_posts['type'];
$product = new Products($new_product); 
$product->save();

您无需使用公司和类型模型来建立它们与产品之间的关系。你可以简单填写ID。

插入具有一对多关系的数据

1 个答案: