Question

在mysql中按大小列出数据库顺序中所有表的查询是什么？

Answer 1

试试这个......

SELECT TABLE_NAME, table_rows, data_length, index_length, 
round(((data_length + index_length) / 1024 / 1024),2) "Size in MB"
FROM information_schema.TABLES WHERE table_schema = "schema_name"
ORDER BY (data_length + index_length) DESC;

问候。

Answer 2

在mysql客户端

中运行以下查询

<!DOCTYPE html>

<html>
<head>
    <meta name="viewport" content="width=device-width" />
    <title>@ViewBag.Title</title>

    @Scripts.Render("~/bundles/modernizr")
    @Styles.Render("~/Content/css")

</head>
<body>

    @{Html.RenderPartial("_NavBar");}

    <div class="container" id="MainBody">
        @RenderBody()
    </div>

    @Scripts.Render("~/bundles/jquery")
    @Scripts.Render("~/bundles/bootstrap")
    @RenderSection("scripts", false)

</body>
</html>

Answer 3

在information_schema数据库中执行以下查询：

SELECT table_schema AS "Database name",
SUM(data_length + index_length) / 1024 / 1024 AS "Size (MB)" 
FROM information_schema.TABLES 
GROUP BY table_schema 
ORDER BY (SUM(data_length + index_length) / 1024 / 1024) DESC;

Mysql列表表和大小 - 按大小排序

3 个答案: