Question

我有一个相当简单的HttpClient 4代码，它调用HttpGet来获取HTML输出。 HTML返回脚本和图像位置都设置为本地（例如<img src="/images/foo.jpg"/>）所以我需要调用URL使这些成为绝对（<img src="http://foo.com/images/foo.jpg"/>）现在出现问题 - 在调用期间可能有一个或两个302重定向，因此原始URL不再反映HTML的位置。

如果我可能（或可能不）拥有所有重定向，我如何获取返回内容的最新网址？

我查看了HttpGet#getAllHeaders()和HttpResponse#getAllHeaders() - 找不到任何内容。

已编辑：HttpGet#getURI()返回原始致电地址

Answer 1

这将是当前的URL，您可以通过调用

获取

  HttpGet#getURI();

编辑：你没有提到你是如何进行重定向的。这对我们有用，因为我们自己处理302.

听起来像是在使用DefaultRedirectHandler。我们曾经这样做过。获取当前URL非常棘手。您需要使用自己的上下文。以下是相关的代码段，

        HttpGet httpget = new HttpGet(url);
        HttpContext context = new BasicHttpContext(); 
        HttpResponse response = httpClient.execute(httpget, context); 
        if (response.getStatusLine().getStatusCode() != HttpStatus.SC_OK)
            throw new IOException(response.getStatusLine().toString());
        HttpUriRequest currentReq = (HttpUriRequest) context.getAttribute( 
                ExecutionContext.HTTP_REQUEST);
        HttpHost currentHost = (HttpHost)  context.getAttribute( 
                ExecutionContext.HTTP_TARGET_HOST);
        String currentUrl = (currentReq.getURI().isAbsolute()) ? currentReq.getURI().toString() : (currentHost.toURI() + currentReq.getURI());

默认重定向对我们不起作用所以我们改了但是我忘记了问题是什么。

Answer 2

在HttpClient 4中，如果您使用LaxRedirectStrategy或DefaultRedirectStrategy的任何子类，这是推荐的方式（请参阅DefaultRedirectStrategy的源代码）：

HttpContext context = new BasicHttpContext();
HttpResult<T> result = client.execute(request, handler, context);
URI finalUrl = request.getURI();
RedirectLocations locations = (RedirectLocations) context.getAttribute(DefaultRedirectStrategy.REDIRECT_LOCATIONS);
if (locations != null) {
    finalUrl = locations.getAll().get(locations.getAll().size() - 1);
}

从HttpClient 4.3.x开始，上面的代码可以简化为：

HttpClientContext context = HttpClientContext.create();
HttpResult<T> result = client.execute(request, handler, context);
URI finalUrl = request.getURI();
List<URI> locations = context.getRedirectLocations();
if (locations != null) {
    finalUrl = locations.get(locations.size() - 1);
}

Answer 3

    HttpGet httpGet = new HttpHead("<put your URL here>");
    HttpClient httpClient = HttpClients.createDefault();
    HttpClientContext context = HttpClientContext.create();
    httpClient.execute(httpGet, context);
    List<URI> redirectURIs = context.getRedirectLocations();
    if (redirectURIs != null && !redirectURIs.isEmpty()) {
        for (URI redirectURI : redirectURIs) {
            System.out.println("Redirect URI: " + redirectURI);
        }
        URI finalURI = redirectURIs.get(redirectURIs.size() - 1);
    }

Answer 4

基于ZZ Coder解决方案的IMHO改进方法是使用ResponseInterceptor简单地跟踪最后的重定向位置。这样你就不会丢失信息，例如在标签之后。如果没有响应拦截器，则会丢失主题标签。示例：http://j.mp/OxbI23

private static HttpClient createHttpClient() throws NoSuchAlgorithmException, KeyManagementException {
    SSLContext sslContext = SSLContext.getInstance("SSL");
    TrustManager[] trustAllCerts = new TrustManager[] { new TrustAllTrustManager() };
    sslContext.init(null, trustAllCerts, new java.security.SecureRandom());

    SSLSocketFactory sslSocketFactory = new SSLSocketFactory(sslContext);
    SchemeRegistry schemeRegistry = new SchemeRegistry();
    schemeRegistry.register(new Scheme("https", 443, sslSocketFactory));
    schemeRegistry.register(new Scheme("http", 80, new PlainSocketFactory()));

    HttpParams params = new BasicHttpParams();
    ClientConnectionManager cm = new org.apache.http.impl.conn.SingleClientConnManager(schemeRegistry);

    // some pages require a user agent
    AbstractHttpClient httpClient = new DefaultHttpClient(cm, params);
    HttpProtocolParams.setUserAgent(httpClient.getParams(), "Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:13.0) Gecko/20100101 Firefox/13.0.1");

    httpClient.setRedirectStrategy(new RedirectStrategy());

    httpClient.addResponseInterceptor(new HttpResponseInterceptor() {
        @Override
        public void process(HttpResponse response, HttpContext context)
                throws HttpException, IOException {
            if (response.containsHeader("Location")) {
                Header[] locations = response.getHeaders("Location");
                if (locations.length > 0)
                    context.setAttribute(LAST_REDIRECT_URL, locations[0].getValue());
            }
        }
    });

    return httpClient;
}

private String getUrlAfterRedirects(HttpContext context) {
    String lastRedirectUrl = (String) context.getAttribute(LAST_REDIRECT_URL);
    if (lastRedirectUrl != null)
        return lastRedirectUrl;
    else {
        HttpUriRequest currentReq = (HttpUriRequest) context.getAttribute(ExecutionContext.HTTP_REQUEST);
        HttpHost currentHost = (HttpHost)  context.getAttribute(ExecutionContext.HTTP_TARGET_HOST);
        String currentUrl = (currentReq.getURI().isAbsolute()) ? currentReq.getURI().toString() : (currentHost.toURI() + currentReq.getURI());
        return currentUrl;
    }
}

public static final String LAST_REDIRECT_URL = "last_redirect_url";

就像ZZ Coder的解决方案一样使用它：

HttpResponse response = httpClient.execute(httpGet, context);
String url = getUrlAfterRedirects(context);

Answer 5

我认为找到最后一个网址的更简单方法是使用DefaultRedirectHandler。

package ru.test.test;

import java.net.URI;

import org.apache.http.HttpResponse;
import org.apache.http.ProtocolException;
import org.apache.http.impl.client.DefaultRedirectHandler;
import org.apache.http.protocol.HttpContext;

public class MyRedirectHandler extends DefaultRedirectHandler {

    public URI lastRedirectedUri;

    @Override
    public boolean isRedirectRequested(HttpResponse response, HttpContext context) {

        return super.isRedirectRequested(response, context);
    }

    @Override
    public URI getLocationURI(HttpResponse response, HttpContext context)
            throws ProtocolException {

        lastRedirectedUri = super.getLocationURI(response, context);

        return lastRedirectedUri;
    }

}

使用此处理程序的代码：

  DefaultHttpClient httpclient = new DefaultHttpClient();
  MyRedirectHandler handler = new MyRedirectHandler();
  httpclient.setRedirectHandler(handler);

  HttpGet get = new HttpGet(url);

  HttpResponse response = httpclient.execute(get);

  HttpEntity entity = response.getEntity();
  lastUrl = url;
  if(handler.lastRedirectedUri != null){
      lastUrl = handler.lastRedirectedUri.toString();
  }

Answer 6

我在HttpComponents Client Documentation

上找到了这个

CloseableHttpClient httpclient = HttpClients.createDefault();
HttpClientContext context = HttpClientContext.create();
HttpGet httpget = new HttpGet("http://localhost:8080/");
CloseableHttpResponse response = httpclient.execute(httpget, context);
try {
    HttpHost target = context.getTargetHost();
    List<URI> redirectLocations = context.getRedirectLocations();
    URI location = URIUtils.resolve(httpget.getURI(), target, redirectLocations);
    System.out.println("Final HTTP location: " + location.toASCIIString());
    // Expected to be an absolute URI
} finally {
    response.close();
}

Answer 7

在2.3版中，Android仍然不支持以下重定向（HTTP代码302）。我刚读了位置标题并再次下载：

if (statusCode != HttpStatus.SC_OK) {
    Header[] headers = response.getHeaders("Location");

    if (headers != null && headers.length != 0) {
        String newUrl = headers[headers.length - 1].getValue();
        // call again the same downloading method with new URL
        return downloadBitmap(newUrl);
    } else {
        return null;
    }
}

此处没有循环重定向保护，所以要小心。更多信息，请访问博客Follow 302 redirects with AndroidHttpClient

Answer 8

这就是我设法获取重定向网址的原因：

Header[] arr = httpResponse.getHeaders("Location");
for (Header head : arr){
    String whatever = arr.getValue();
}

或者，如果您确定只有一个重定向位置，请执行以下操作：

httpResponse.getFirstHeader("Location").getValue();

HttpClient 4 - 如何捕获上次重定向URL

8 个答案: