Question

基本上我要做的是计算CreditPayments的平均百分比和预计期间CashPayments的平均百分比（回顾3个月，然后是过去六个月中所有正确类型的付款人）

因此，如果平均值（在正确的回顾期间）= 75％信用＆amp; 25％现金然后我那个月的未结A / R我可以反对什么％将是Credit＆amp;什么％将是现金。我希望运行它12个月，每个MOS的回顾都会改变。

现在我的结果总是0，这显然是错误的。我知道最初的内部查询是正确的;但是，外部查询运行时会发生问题。我认为问题在于T1。 MOS，我认为限制了结果。任何帮助将不胜感激。

SELECT
    T1.Facility Facility
    , T1.CustType CustType
    , T1.MOS MOS
    , SUM(CASE WHEN (T1.MOS BETWEEN ADD_MONTHS(T1.MOS,-9) AND (ADD_MONTHS(T1.MOS,-3)-1) THEN T1.CredPmts ELSE 0 END)/SUM(CASE WHEN (T1.MOS BETWEEN ADD_MONTHS(T1.MOS,-9) AND (ADD_MONTHS(T1.MOS,-3)-1) THEN T1.Charges ELSE 0 END)
    , SUM(CASE WHEN (T1.MOS BETWEEN ADD_MONTHS(T1.MOS,-9) AND (ADD_MONTHS(T1.MOS,-3)-1) THEN T1.CashPmts ELSE 0 END)/SUM(CASE WHEN (T1.MOS BETWEEN ADD_MONTHS(T1.MOS,-9) AND (ADD_MONTHS(T1.MOS,-3)-1) THEN T1.Charges ELSE 0 END)
FROM
(
SELECT
    T.FACILITY Facility
    , T.CUSTTYPE CustType
    , trunc(to_date(T.SERVICEDATE,'j'),'MONTH') MOS
    , SUM(CASE WHEN T.TYPE = 'C' THEN T.AMOUNT ELSE 0 END) Charges
    , SUM(CASE WHEN (T.TYPE IN ('P1','62','12','75','P6','23') THEN T.AMOUNT ELSE 0 END CredPmts
    , SUM(CASE WHEN (T.TYPE IN ('92','57','P3','P9','26','39') THEN T.AMOUNT ELSE 0 END CashPmts
FROM TRANSTABLE T
WHERE
    T.FACILITY = '123'
    AND T.SERVICEDATE BETWEEN to_char(ADD_MONTHS(to_date('20120101', 'yyyymmdd'),-9), 'j') AND to_char(to_date('20121231', 'yyyymmdd'), 'j')
GROUP BY
    T.FACILITY
    , T.CUSTTYPE
    , trunc(to_date(T.SERVICEDATE,'j'),'MONTH')
)T1
GROUP BY
    T1.Facility
    , T1.CustType
    , T1.MOS

Answer 1

外部查询的CASE WHEN子句中有不匹配的括号：

WHEN (T1.MOS BETWEEN ADD_MONTHS(T1.MOS,-9) AND (ADD_MONTHS(T1.MOS,-3)-1)的）

所有四个地方。你能检查一下吗？

Oracle SQL表达式基于所选月份的六个月付款总额

1 个答案: