Question

我知道这听起来很荒谬......我知道......但我希望能够选择一个月的前7天并得到这样的结果。

这就是我所拥有的：

SELECT row_number () OVER (ORDER BY DateD), *
  FROM (SELECT DATENAME (dw, GETDATE ()) AS 'DateName', getdate () AS 'DateD'
        UNION
        SELECT DATENAME (dw, GETDATE () + 1) AS 'DateName',
               getdate () + 1 AS 'DateD'
        UNION
        SELECT DATENAME (dw, GETDATE () + 2) AS 'DateName',
               getdate () + 2 AS 'DateD'
        UNION
        SELECT DATENAME (dw, GETDATE () + 3) AS 'DateName',
               getdate () + 3 AS 'DateD'
        UNION
        SELECT DATENAME (dw, GETDATE () + 4) AS 'DateName',
               getdate () + 4 AS 'DateD'
        UNION
        SELECT DATENAME (dw, GETDATE () + 5) AS 'DateName',
               getdate () + 5 AS 'DateD'
        UNION
        SELECT DATENAME (dw, GETDATE () + 6) AS 'DateName',
               getdate () + 6 AS 'DateD') queryTable

Answer 1

这是一个非常丑陋的查询，可以为您提供结果：

SELECT row_number () OVER (ORDER BY DateD), *
FROM 
(
    SELECT DATENAME (dw, DATEADD(month, DATEDIFF(month, 0, getdate()), 0)) AS 'DateName', 
        DATEADD(month, DATEDIFF(month, 0, getdate()), 0) AS 'DateD'
    UNION
    SELECT DATENAME (dw, DateAdd(day, 1, DATEADD(month, DATEDIFF(month, 0, getdate()), 0))) AS 'DateName',
           DateAdd(day, 1, DATEADD(month, DATEDIFF(month, 0, getdate()), 0)) AS 'DateD'
    UNION
    SELECT DATENAME (dw, DateAdd(day, 2, DATEADD(month, DATEDIFF(month, 0, getdate()), 0))) AS 'DateName',
           DateAdd(day, 2, DATEADD(month, DATEDIFF(month, 0, getdate()), 0)) AS 'DateD'
    UNION
    SELECT DATENAME (dw, DateAdd(day, 3, DATEADD(month, DATEDIFF(month, 0, getdate()), 0))) AS 'DateName',
           DateAdd(day, 3, DATEADD(month, DATEDIFF(month, 0, getdate()), 0)) AS 'DateD'
    UNION
    SELECT DATENAME (dw, DateAdd(day, 4, DATEADD(month, DATEDIFF(month, 0, getdate()), 0))) AS 'DateName',
           DateAdd(day, 4, DATEADD(month, DATEDIFF(month, 0, getdate()), 0)) AS 'DateD'
    UNION
    SELECT DATENAME (dw, DateAdd(day, 5, DATEADD(month, DATEDIFF(month, 0, getdate()), 0))) AS 'DateName',
           DateAdd(day, 5, DATEADD(month, DATEDIFF(month, 0, getdate()), 0)) AS 'DateD'
    UNION
    SELECT DATENAME (dw, DateAdd(day, 6, DATEADD(month, DATEDIFF(month, 0, getdate()), 0))) AS 'DateName',
           DateAdd(day, 6, DATEADD(month, DATEDIFF(month, 0, getdate()), 0)) AS 'DateD'
) queryTable

请参阅SQL Fiddle with Demo

Answer 2

这是一种在当月获得@n天的简单方法。如果您在不同的月份需要它，只需将GETDATE()替换为表示您想要的月内任何日期时间值的变量。

;WITH x AS 
(
  SELECT TOP (@n) n = ROW_NUMBER() OVER (ORDER BY [object_id])
  FROM sys.all_objects
),
y(d,n) AS
(
  SELECT DATEADD(DAY, n-1, DATEADD(MONTH, DATEDIFF(MONTH, 0, GETDATE()), 0)),
   n FROM x
)
SELECT 
  RowNumber = n, 
  [Weekday] = DATENAME(WEEKDAY, d), 
  [Date_In_Ambiguous_Format] = CONVERT(CHAR(10), d, 101),
  [Date_In_Proper_DataType] = d
FROM y;

请参阅此博客系列，了解如何生成没有循环的集合而不重复代码：

http://www.sqlperformance.com/2013/01/t-sql-queries/generate-a-set-1
http://www.sqlperformance.com/2013/01/t-sql-queries/generate-a-set-2
http://www.sqlperformance.com/2013/01/t-sql-queries/generate-a-set-3

Answer 3

您可以使用此递归CTE：

WITH dayscte ( d ) 
     AS (SELECT DATEADD(DAY, 0, DATEADD(MONTH, DATEDIFF(MONTH, 0, GETDATE()), 0)) AS d 
         UNION ALL 
         SELECT Dateadd(d, 1, d) 
         FROM   dayscte 
         WHERE  Datepart(day, d) < 7)  -- number of days you want
SELECT d, 
       Datepart(wk, d) AS week_number, 
       Datename(dw, d) AS day_name, 
       Datename(m, d)  AS month_name, 
       Datename(q, d)  AS [quarter] 
FROM   dayscte 
OPTION (maxrecursion 800);

Demo

Answer 4

WITH Dates AS
(
    SELECT DATEADD(DAY, - (DATEPART(DAY, GETDATE()) - 1), CONVERT(VARCHAR, GETDATE(), 101)) as DateDay
    UNION ALL
    SELECT DateDay + 1
    FROM Dates
    WHERE DATEPART(DAY, DateDay) < 7
)

SELECT
    DATEPART(DAY, DateDay),
    DATENAME(DW, DateDay),
    DateDay
FROM Dates

Answer 5

使用SQL Server，您可以查询master..spt_values以获取数字列表（不是整个数字列表，但绝对是1到7）：

SELECT 
   row_number () OVER (ORDER BY Number) as Row, 
   DATENAME (dw,CONVERT(VARCHAR(25),DATEADD(dd,-(DAY(GetDate())-Number),GetDate()),101) ) AS DtName,
   CONVERT(VARCHAR, CONVERT(VARCHAR(25),DATEADD(dd,-(DAY(GetDate())-Number),GetDate()),101), 101) As Dt
FROM (SELECT Number FROM master..spt_values WHERE Number BETWEEN 1 AND 7 AND Type = 'P') t

另一种方法 - 玩得开心！这是Fiddle。

祝你好运。

一个月中的几天

5 个答案: