Android - 如何从字符串解析JsonArray?

时间:2013-01-28 16:28:00

标签: android json

我正在尝试从json字符串解析json数组,但它总是抛出异常data of type java.lang.String cannot be converted to JSONArray

如果我犯了任何错误,请告诉我。

感谢。

以下是从服务器获取Json的代码:

try {
                String url = String.format(<url here>, province.provinceCode2);
                HttpClient httpClient = getHttpClient();
                HttpGet httpGet = new HttpGet(url);
                HttpResponse httpResponse = httpClient.execute(httpGet);
                HttpEntity entity = httpResponse.getEntity();
                final String result = EntityUtils.toString(entity);
                parseAndSaveJsonData(province, result);
            } catch (Exception e) {
                e.printStackTrace();
            }

这里是解析JsonArray的代码:

String jsonString = <below json string>
JSONArray ja = new JSONArray(jsonString);

这是我的json字符串:

   [
   {
      "LotPrizes":[
         {
            "Prize":"Giảitám",
            "Range":"50"
         },
         {
            "Prize":"Giảibảy",
            "Range":"264"
         },
         {
            "Prize":"Giảisáu",
            "Range":"3654-5162-3097"
         },
         {
            "Prize":"Giảinăm",
            "Range":"9739"
         },
         {
            "Prize":"Giảitư",
            "Range":"97690-99274-32442-69432-04855-10132-17085"
         },
         {
            "Prize":"Giảiba",
            "Range":"73745-13007"
         },
         {
            "Prize":"Giảinhì",
            "Range":"05521"
         },
         {
            "Prize":"Giảinhất",
            "Range":"74870"
         },
         {
            "Prize":"GiảiDB6",
            "Range":"878833"
         }
      ]
      },
 {
      "LotPrizes":[
         {
            "Prize":"Giảitám",
            "Range":"50"
         },
         {
            "Prize":"Giảibảy",
            "Range":"264"
         },
         {
            "Prize":"Giảisáu",
            "Range":"3654-5162-3097"
         },
         {
            "Prize":"Giảinăm",
            "Range":"9739"
         },
         {
            "Prize":"Giảitư",
            "Range":"97690-99274-32442-69432-04855-10132-17085"
         },
         {
            "Prize":"Giảiba",
            "Range":"73745-13007"
         },
         {
            "Prize":"Giảinhì",
            "Range":"05521"
         },
         {
            "Prize":"Giảinhất",
            "Range":"74870"
         },
         {
            "Prize":"GiảiDB6",
            "Range":"878833"
         }
      ]
      }

    ]

3 个答案:

答案 0 :(得分:15)

这是初始化JSON解析器的方法:

JSONObject jsonObject = new JSONObject(jsonString);

这将为您提供整个字符串作为Json对象。从那里,拉出一个单独的数组作为JsonArray,如下所示:

JSONArray jsonArray = jsonObject.getJSONArray("LotPrizes");

要访问每个“LotPrizes”,您可以使用循环逻辑:

for(int i=0;i<jsonArray.length();i++)
{
  JSONObject curr = jsonArray.getJSONObject(i);

  prize = curr.getString("Prize")

//Do stuff with the Prize String here
//Add it to a list, print it out, etc.
}

编辑: JSON编辑后的最终代码:

JSONArray jsonArray = null;
String jsonString = <your string>
String currPrize = null;

JSONObject jsonObject = new JSONObject(jsonString);

jsonArray = jsonObject.getJSONArray("data");

for(int i=0;i<jsonArray.length();i++)
{
    JSONArray currLot = jsonArray.getJSONObject(i);

    for(int j=0; j<currLot.length();j++)
    {
        JSONobject curr = currLot.getJSONObject(j);

        currPrize = curr.getString("Prize");

        //Do something with Prize
    }
}

此代码功能正常,我在代码中使用的版本几乎相同。希望这(终于)适合你。

答案 1 :(得分:2)

你好@Caerulius,Harish,ρяσѕρєяK,Hot Licks等等。 最后,经过2天的头痛和2个不眠之夜,我解决了这个问题。因为你花了宝贵的时间与我讨论,我看到我必须告诉你根本原因。这是我的责任。

首先,我是一名高级Android开发人员。所以,我至少知道JSON基本知识,我知道如何从JSON字符串解析数据,我知道很多有用的在线工具来验证它。我确认我从服务器获得的JSON字符串是有效的。

正如我在问题中所说,我使用final String result = EntityUtils.toString(entity);HttpEntity对象获取JSON字符串。我过去曾多次使用它并且它有效。没问题。但是,在这种情况下,它不是。 原始的JSON字符串如下:

   [{
      "LotPrizes":[
         {
            "Prize":"Giảitám",
            "Range":"50"
         },
         {
            "Prize":"Giảibảy",
            "Range":"264"
         },
         ...
    }]

但我得到的是这样的:

"[{
      \"LotPrizes\":[
         {
            \"Prize":\"Giảitám\",
            \"Range\":\"50\"
         },
         {
            \"Prize\":\"Giảibảy\",
            \"Range\":\"264\"
         },
         ...
    }]"

此字符串类似于常量字符串,我们可以声明如下:

String stringVariable = "\"[{
          \\\"LotPrizes\\\":[
             {
                \\\"Prize":\\\"Giảitám\\\",
                \\\"Range\\\":\\\"50\\\"
             },
             {
                \\\"Prize\\\":\\\"Giảibảy\\\",
                \\\"Range\\\":\\\"264\\\"
             },
             ...
        }]\" ;

这是一个有效的字符串,但不是有效的JSON字符串。

要解决此问题,我改变了获取JSON字符串的方式,并删除了不必要的字符,如下所示:

                            HttpClient httpClient = getHttpClient();
                HttpGet httpGet = new HttpGet(url);
                HttpResponse httpResponse = httpClient.execute(httpGet);
                HttpEntity entity = httpResponse.getEntity();
                InputStream is = entity.getContent();
                BufferedReader reader = new BufferedReader(new InputStreamReader(is, "UTF-8"), 8);
                StringBuilder sb = new StringBuilder();
                String line = null;
                while ((line = reader.readLine()) != null) {
                    sb.append(line + "\n");
                }
                is.close();
                String json = sb.toString();

                json = json.replace("\\", "");
                json = json.substring(1);
                json = json.substring(0, json.length() - 2);

现在,json变量包含我可以正确解析的JSON字符串。我认为这应该是HttpEntity库的一个bug。

希望这有助于其他人。

答案 2 :(得分:1)

您可以从字符串中检索jsondata,如下所示..

            JSONObject json = new JSONObject(jsonString);
            JSONArray jData = json.getJSONArray("data");
            for (int i = 0; i < jData.length(); i++) {
                JSONObject jo = jData.getJSONObject(i);

                JSONArray jLotPrizes = jo.getJSONArray("LotPrizes");
                for (int j = 0; j < jLotPrizes.length(); j++) {
                    JSONObject jobj = jLotPrizes.getJSONObject(j);

                    Log.i("Prize", "" + jobj.getString("Prize"));
                    Log.i("Range", "" + jobj.getString("Range"));
                }

            }