NumberFormatException:无效的int:“1”

时间:2013-01-28 15:40:17

标签: java android algorithm loops .obj

我正在尝试制作一个简单的算法,将.obj文件转换为我的程序可以使用的数据。

这是输入字符串数据示例: “v 1.000000 -1.000000 -1.000000” “f 1 2 3 4”

file = new BufferedReader(new InputStreamReader(am.open("test.obj"))); //Loads the .obj
        String out = " ";
        try{
            while((out=file.readLine()) != null){ //Grabs a line from the file and checks so that it aint null
                int index = 1;
                int nextIndex = 1;
                if(out.startsWith("v")){Log.w("OBJs", out); //If line starts with "v", go ahead
                    while(index != out.lastIndexOf(" ")){ //checks so the index is not the last index of an empty space " "
                        nextIndex = out.indexOf(" ", index +1); //Looks for the next occurance of an empty space from +1 of current empty space
                        vertices.add(Float.valueOf(out.substring(index, nextIndex))); //Grabs the string in between the two spaces
                        index = nextIndex;// 
                        }
                    vertices.add(Float.valueOf(out.substring(index, out.length())));//Grabs the last variable from the file as the above while is now false
                    }

                int index2 = 1;
                int nextIndex2 = 1;
                if(out.startsWith("f")){Log.w("OBJs", out);// THis works exactly as above, gives error and i dunno why
                    while(index2 != out.lastIndexOf(" ")){
                        nextIndex2 = out.indexOf(" ", index2 +1);
                        edges.add(Integer.valueOf(out.substring(index2, nextIndex2)));
                        Log.w("OBJs", out.substring(index2, nextIndex2)); 
                        index2 = nextIndex2;

                    }
                    edges.add(Integer.valueOf(out.substring(index2, out.length())));
                }

            }
        }

这导致:

FATAL EXCEPTION: main
java.lang.RuntimeException: Unable to start activity ComponentInfo{my.stuffs.blodvite/my.stuffs.blodvite.MainActivity}: java.lang.NumberFormatException: Invalid int: " 1"

这只发生在第二个循环段,我正在尝试收集面部信息。收集顶点可以完美地工作,我使用完全相同的算法,所以我不明白问题是什么。 还有一点值得注意的是,当我上次关闭eclipse时,我觉得它确实有效,不知道发生了什么,或者我是否记得错了。哦,正如您从代码中看到的那样,它将其读取行打印到Log cat。这就是结果。

01-26 23:42:13.916: W/OBJs(18442): v 1.000000 -1.000000 -1.000000
01-26 23:42:13.916: W/OBJs(18442): v 1.000000 -1.000000 1.000000
01-26 23:42:13.916: W/OBJs(18442): v -1.000000 -1.000000 1.000000
01-26 23:42:13.916: W/OBJs(18442): v -1.000000 -1.000000 -1.000000
01-26 23:42:13.916: W/OBJs(18442): v 1.000000 1.000000 -0.999999
01-26 23:42:13.916: W/OBJs(18442): v 0.999999 1.000000 1.000001
01-26 23:42:13.916: W/OBJs(18442): v -1.000000 1.000000 1.000000
01-26 23:42:13.916: W/OBJs(18442): v -1.000000 1.000000 -1.000000
01-26 23:42:13.916: W/OBJs(18442): f 1 2 3 4

因此,它清楚地显示顶点采​​集没有错误,但是面部聚集在第一次迭代时停止。

1 个答案:

答案 0 :(得分:1)

这是因为您在“1”中有一个前导空格。正如@Raghav Sood已经指出的那样,在尝试解析为int以使其工作之前,您可以在Strings上调用trim。您也可以简单地从index2 + 1开始获取子字符串(即跳过第一个空格)。

我很好奇你为什么不直接使用StringTokenizer。