Question

我正在尝试在我们的售票网站上整理用户的实时视图。

目前，我在网站上有2个会话（Session col）。我当前的查询返回以下内容：

EVENTID     EVENT      Session    SessionOpened           SessionLength   NumberofTix
1619        BB King     11         2013-01-28 09:34:16.300   -2            2
1622        BB King     12         2013-01-28 09:36:55.073    0            1
1622        BB King     12         2013-01-28 09:36:55.077    0            3

但是，它应该是这样的：

EVENTID     EVENT      Session    SessionOpened           SessionLength   NumberofTix
1619        BB King     11         2013-01-28 09:34:16.300   -2            2
1622        BB King     12         2013-01-28 09:36:55.073    0            4

为什么Session 12返回2行-1，1张票，1张3票？

查询：

SELECT distinct set_eSRO_Event as EventID, shName as EventName, setSRO_UID as SRO_SessionID, setDateTime as SessionStarted, 
DATEDIFF(mi, getDate(), setDateTime) as SessionTimer, Count(*) AS NumberofTickets FROM SessionTickets
INNER JOIN Shows on shCode = setShowCode
WHERE setStatus = 0
GROUP BY setsro_UID, shName, set_eSRO_Event, setDateTime

Answer 1

你的结果列和查询的别名不一致，很难说。我认为setDateTime是不同的（= SessionStarted或SessionOpened）。当您按setDatetime分组时，如果它们不同=＆gt;两行。

因此，为setDatetime添加MIN聚合函数（如在“想要的”结果中），并从GROUP BY中删除setDatetime

SELECT set_eSRO_Event as EventID, 
shName as EventName, 
setSRO_UID as SRO_SessionID, 
MIN(setDateTime) as SessionStarted, 
DATEDIFF(mi, getDate(), MIN(setDateTime)) as SessionTimer, 
COUNT(*) AS NumberofTickets 
FROM SessionTickets
INNER JOIN Shows on shCode = setShowCode
WHERE setStatus = 0
GROUP BY setsro_UID, shName, set_eSRO_Event

Answer 2

如果不知道哪个列属于哪个表，以及SQL Server的版本，您可以尝试以下查询：

SELECT  EventID, 
        EventName, 
        SRO_SessionID, 
        MIN(SessionStarted) SessionStarted, 
        SessionTimer,
        SUM(NumberofTickets) NumberofTickets
FROM (  SELECT  set_eSRO_Event as EventID, 
                shName as EventName, 
                setSRO_UID as SRO_SessionID, 
                setDateTime as SessionStarted, 
                DATEDIFF(mi, getDate(), setDateTime) as SessionTimer, 
                Count(*) AS NumberofTickets 
        FROM SessionTickets 
        INNER JOIN Shows 
            ON shCode = setShowCode
        WHERE setStatus = 0
        GROUP BY set_eSRO_Event, shName, setSRO_UID, setDateTime,
                 DATEDIFF(mi, getDate(), setDateTime)) A
GROUP BY EventID, EventName, SRO_SessionID, SessionTimer

计算会话ID出现的次数（MSSQL）

2 个答案: