Question

我有以下后台作业写入csv文件并通过电子邮件发送出去。我正在使用Tempfile类，因此在将其通过电子邮件发送给用户后，该文件将被删除。目前，当我查看csv文件时，我生成的结果如下所示：

["Client Application"    "Final Price"   "Tax"   "Credit"    "Base Price"    "Billed At"     "Order Guid"    "Method of Payment Guid"    "Method of Payment Type"]
["web"   nil     nil     nil     nil     nil     nil     "k32k313k1j3"   "credit card"]

请忽略这些数据，但问题是，它是以ruby格式直接写入文件而不是删除“”和[]字符。

请参阅以下代码：

class ReportJob
@queue = :report_job

 def self.perform(client_app_id, current_user_id)
  user = User.find(current_user_id)
  client_application = Application.find(client_app_id)
  transactions = client_application.transactions
  file = Tempfile.open(["#{Rails.root}/tmp/", ".csv"]) do |csv|
    begin
     csv << ["Application", "Price", "Tax", "Credit", "Base Price", "Billed At", "Order ID", "Payment ID", "Payment Type"]
     transactions.each do |transaction|
      csv << "\n"
      csv << [application.name, transaction.price, transaction.tax, transaction.credit, transaction.base_price, transaction.billed_at, transaction.order_id, transaction.payment_id, transaction.payment_type]
    end
   ensure
    ReportMailer.send_rev_report(user.email, csv).deliver
    csv.close(unlink_now=false)
    end
  end
end

end

使用tempfile类而不是csv类会有问题吗？或者我有什么办法可以改变它写入文件的方式？

添加用于在邮件程序中读取csv文件的代码。我目前收到一个TypeError，上面写着“无法将CSV转换为字符串”。

class ReportMailer < ActionMailer::Base
 default :from => "test@gmail.com"

  def send_rev_report(email, file)
     attachments['report.csv'] = File.read("#{::Rails.root.join('tmp', file)}")
      mail(:to => email, :subject => "Attached is your report")
    end
  end
end

Answer 1

问题是你实际上并没有将csv数据写入文件。您正在向文件句柄发送数组。我相信你需要这样的东西：

Tempfile.open(....) do |fh|
    csv = CSV.new(fh, ...)
    <rest of your code>
end

正确设置CSV输出过滤。

Answer 2

试试这个：

Tempfile.open(["#{Rails.root}/tmp/", ".csv"]) do |outfile|
  CSV::Writer.generate(outfile) do |csv|
    csv << ["Application", "Price", "Tax", "Credit", "Base Price", "Billed At", "Order ID", "Payment ID", "Payment Type"]
    #...
  end
end

Answer 3

我更喜欢

tempfile = Tempfile.new(....)
csv = CSV.new(tempfile, ...) do |row|
  <rest of your code>
end

Answer 4

这就是我的做法。

patient_payments = PatientPayment.all

Tempfile.new(['patient_payments', '.csv']).tap do |file|
  CSV.open(file, 'wb') do |csv|
    csv << patient_payments.first.class.attribute_names

    patient_payments.each do |patient_payment|
      csv << patient_payment.attributes.values
    end
  end
end

在Ruby中通过Tempfile写入文件

4 个答案: