Question

因此，我尝试在“警报对话”框中创建一个联系表单，该框从菜单选项打开。我的表单中有3个EditText字段，在我的Main.java中，当按下表单中的“发送”按钮时，我从那些字段中读取，然后我启动了电子邮件意图，或者至少那是它应该做的事情。现在，只要按下发送按钮，应用就会崩溃。现在我已经解决了这个问题并且它似乎没有出现在意图中，但是当我从EditText字段中读取时它就出现了。当我取出EditText读取部分并将填充信息放在其位置时，代码工作正常，但我需要使用EditTexts。谢谢。我在菜单中选项的完整代码：

case R.id.menu_feedback:

    AlertDialog.Builder builder = new AlertDialog.Builder(this);
builder.setTitle(R.string.menu_feedback);
LayoutInflater inflater = this.getLayoutInflater();

// Inflate and set the layout for the dialog
// Pass null as the parent view because its going in the dialog layout
builder.setView(inflater.inflate(R.layout.feedback, null));
// Add the buttons
builder.setNegativeButton(R.string.send, new DialogInterface.OnClickListener() {
       public void onClick(DialogInterface dialog, int id) {
           // User clicked OK button
           final EditText nameField = (EditText) findViewById(R.id.EditTextName);
           String name = nameField.getText().toString();
           final EditText emailField = (EditText) findViewById(R.id.EditTextEmail);
           String email = emailField.getText().toString();
           final EditText feedbackField = (EditText) findViewById(R.id.EditTextFeedbackBody);
           String feedback = feedbackField.getText().toString();
           final CheckBox responseCheckbox = (CheckBox) findViewById(R.id.CheckBoxResponse);
           boolean bRequiresResponse = responseCheckbox.isChecked();

           /* Create the Intent */
           final Intent emailIntent = new Intent(android.content.Intent.ACTION_SEND);

           /* Fill it with Data */
           emailIntent.setType("plain/text");
           emailIntent.putExtra(android.content.Intent.EXTRA_EMAIL, R.string.send_email);
           emailIntent.putExtra(android.content.Intent.EXTRA_SUBJECT, "Subject");
           emailIntent.putExtra(android.content.Intent.EXTRA_TEXT, feedback);

           /* Send it off to the Activity-Chooser */
           startActivity(Intent.createChooser(emailIntent, "Send mail..."));
           dialog.dismiss();

       }
   });
builder.setPositiveButton(R.string.cancel, new DialogInterface.OnClickListener() {
           public void onClick(DialogInterface dialog, int id) {
               dialog.dismiss();
           }
       });

// create alert dialog
AlertDialog alertDialog = builder.create();

// show it
alertDialog.show();

return true;

Answer 1

好的，我假设您的所有EditTexts都写在AlertDialog的feedback layout文件中，

View dialogView = inflater.inflate(R.layout.feedback, null);
builder.setView(dialogView );

而Edittext就像，

// User clicked OK button
final EditText nameField = (EditText) dialogView.findViewById(R.id.EditTextName);
String name = nameField.getText().toString();
final EditText emailField = (EditText) dialogView.findViewById(R.id.EditTextEmail);
String email = emailField.getText().toString();
final EditText feedbackField = (EditText) dialogView.findViewById(R.id.EditTextFeedbackBody);
String feedback = feedbackField.getText().toString();

实际上，当您为任何视图充气并且必须使用该视图的子视图时，您必须使用该视图的引用和findViewById()方法。所以在你的情况下，dialogView.findViewById();

Answer 2

使用builder或inflater个实例从AlertDialog访问EditText或其他视图：

 builder.setNegativeButton(R.string.send, new DialogInterface.OnClickListener() {
  public void onClick(DialogInterface dialog, int id) {
                           // User clicked OK button
   final EditText nameField = (EditText)inflater. findViewById(R.id.EditTextName);
   String name = nameField.getText().toString();
   final EditText emailField = (EditText)inflater. 
                                                 findViewById(R.id.EditTextEmail);
   String email = emailField.getText().toString();
   final EditText feedbackField = (EditText)inflater. 
                                          findViewById(R.id.EditTextFeedbackBody);
   String feedback = feedbackField.getText().toString();
// your code here..

当我尝试从EditText捕获时，Android应用程序崩溃

2 个答案: