我正在尝试检查sent1或sent2的长度是否为零,如果他们想要设置 sent_witn_not_null
作为列表,列表为非零 。但是我写的if-else条件似乎令人费解。这样做的简单方法是什么?
sent1 = ["this","is","foo","bar"]
sent2 = []
if len(sent1) or len(sent2) == 0:
sent_with_not_null = sent2 if len(sent1) == 0 else sent1
sent_with_not_null = sent1 if len(sent2) == 0 else sent2
答案 0 :(得分:1)
利用Python的合并运算符。
sent_with_not_null = sent2 and sent1
答案 1 :(得分:1)
这样的东西?
In [4]: if sent1 or sent2:
sent_with_not_null=sent1 if sent1 else sent2
...:
In [5]: sent_with_not_null
Out[5]: ['this', 'is', 'foo', 'bar']
或:
In [11]: if any((sent1,sent2)): #in case both sent1 and sent2 are len==0
sent_with_not_null =sent1 or sent2 #set the first True item to sent_with_not_null
#else the last one
....:
In [12]: sent_with_not_null
Out[12]: ['this', 'is', 'foo', 'bar']