我在菜单系统方面遇到了问题 - 我在这里有一个基本的例子(下图),它显示了我所遵循的基本菜单示例;具体来说,我的问题是如何根据使用菜单选择做出决定,我不确定如何将用户选择与菜单选项进行交互? 有人能指出我正确的方向,或者理想情况下给出一个简单的例子 - 从菜单中输入数据并显示它?
谢谢
import wx
class myFrame(wx.Frame):
def __init__(self, parent, id):
wx.Frame.__init__(self, parent, id,'Menu', size=(300,200))
panel = wx.Panel(self)
status = self.CreateStatusBar()
menubar = wx.MenuBar()
firstMenu = wx.Menu()
secondMenu = wx.Menu()
# create files
firstMenu.Append(wx.NewId(), 'Save Data' , 'Save data')
firstMenu.Append(wx.NewId(), 'Open Data..', 'Open a new window')
secondMenu.Append(wx.NewId(),'Configure..', 'Input Data here')
# append to menu
menubar.Append(firstMenu, 'File')
menubar.Append(secondMenu,'Options')
#
self.SetMenuBar(menubar)
if( __name__ == '__main__' ):
app = wx.PySimpleApp()
frame = myFrame(parent=None, id=-1)
frame.Show()
app.MainLoop()
答案 0 :(得分:2)
您必须绑定wx.EVT_MENU
事件。有关更多示例,请参阅wxPython演示。在你的情况下,这将是一些想法:
import wx
SAVE_DATA = wx.NewId()
OPEN_DATA = wx.NewId()
CONFIGURE = wx.NewId()
class myFrame(wx.Frame):
def __init__(self, parent, id):
wx.Frame.__init__(self, parent, id,'Menu', size=(300,200))
panel = wx.Panel(self)
status = self.CreateStatusBar()
menubar = wx.MenuBar()
firstMenu = wx.Menu()
secondMenu = wx.Menu()
# create files
firstMenu.Append(SAVE_DATA, 'Save Data' , 'Save data')
firstMenu.Append(OPEN_DATA, 'Open Data..', 'Open a new window')
secondMenu.Append(CONFIGURE,'Configure..', 'Input Data here')
# append to menu
menubar.Append(firstMenu, 'File')
menubar.Append(secondMenu,'Options')
#
self.SetMenuBar(menubar)
self.Bind(wx.EVT_MENU, self.SaveData, id=SAVE_DATA)
self.Bind(wx.EVT_MENU, self.OpenData, id=OPEN_DATA)
self.Bind(wx.EVT_MENU, self.Configure, id=CONFIGURE)
def SaveData(self, e):
print("Save")
def OpenData(self, e):
print("Open")
def Configure(self, e):
print("Config")
if( __name__ == '__main__' ):
app = wx.PySimpleApp()
frame = myFrame(parent=None, id=-1)
frame.Show()
app.MainLoop()