Question

我正在使用JSP，Java和PostgreSQL构建一个用于特征提取和比较图像特征的Web应用程序。

我的特征提取是从图像中提取一些特征，然后我可以比较它们（一些特征是关于颜色的，一些特征在图像的直方图上等等。我有特殊的方法使用特定的库提取它们（罐子里面）我添加到lib中，如下例所示！

然后成功将这些功能添加到我的PostgreSQL数据库中。

public void GetImageProperties(String targetPath, ImageProperties imagesProperties) throws Exception
{
    // load image
    FileInputStream imageStream;
    imageStream = new FileInputStream(targetPath);
    BufferedImage bimg = ImageIO.read(imageStream);        

    // get properties
    imagesProperties.cl = new ColorLayoutImpl(bimg);
    imagesProperties.eh = new EdgeHistogramImplementation(bimg);
    imagesProperties.sc = new ScalableColorImpl(bimg);
}

然后我将它们添加到postgresql数据库（只有功能，而不是图像）

String query = "CREATE TABLE Images (" +
               "  imageid SERIAL PRIMARY KEY," +
               "  fname VARCHAR(128)," +
               "  colorlayout VARCHAR(512), " +
               "  edgehist VARCHAR(512), " +
               "  scalablecolor VARCHAR(512) " +
               ")";

每次加载图片时都会收到此错误，并希望将其与目录中的所有其他图像进行比较。

HTTP Status 500 -     
type Exception report

消息：

description The server encountered an internal error () that prevented it from fulfilling this request.

异常：

org.apache.jasper.JasperException: An exception occurred processing JSP page /query.jsp at line 124

121:  if (bSearch) { 
122:    // get form params 
123:    query.setTopK(new Integer(request.getParameter("frm_topk"))); 
124:    query.setColorHistogramWeight(new Integer(request.getParameter("frm_weight_c1"))); 
125:    query.setColorDistributionWeight(new Integer(request.getParameter("frm_weight_c2"))); 
126:    query.setTextureWeight(new Integer(request.getParameter("frm_weight_c3"))); 
127:  }

Stacktrace：

org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:568)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:470)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390)    
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334)   
javax.servlet.http.HttpServlet.service(HttpServlet.java:722)    
org.netbeans.modules.web.monitor.server.MonitorFilter.doFilter(MonitorFilter.java:393)

根本原因：

java.lang.NumberFormatException: For input string: "1.0"
java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)   
java.lang.Integer.parseInt(Integer.java:492)    java.lang.Integer.<init>
(Integer.java:677)  org.apache.jsp.query_jsp._jspService(query_jsp.java:256)    
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)  
javax.servlet.http.HttpServlet.service(HttpServlet.java:722)    
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:432)     
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390)    
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334)   
javax.servlet.http.HttpServlet.service(HttpServlet.java:722)    
org.netbeans.modules.web.monitor.server.MonitorFilter.doFilter(MonitorFilter.java:393)

note The full stack trace of the root cause is available in the Apache Tomcat/7.0.27 logs.

Answer 1

你的问题在这里

query.setTopK(new Integer(request.getParameter("frm_topk")));

应该是

String parFrm_topk = request.getParameter("frm_topk");
Integer frm_topk = null;
if (parFrm_topk != null && parFrm_topk.length() > 0 && !parFrm_topk.equals("null"))
try {
  frm_topk = Integer.valueOf(parFrm_topk);
} catch (NumberFormatException nfe){
  throw nfe;
}
if (frm_topk ! = null) {
   query.setTopK(frm_topk);

此代码正在尝试检查可能为空的参数，为什么它为空取决于应用程序的流程以及参数如何通过url传递。

尝试使用JSP搜索类似图像时出错

1 个答案: