program A {
int x = 10;
tuple date {
int day;
int month;
int year;
}
}
function B {
int y = 20;
...
}
process C {
more code;
}
我想提取A,B,C之后花括号内的任何内容。我编写以下代码,但它不起作用。
public class Test {
public static void main(String[] args) throws IOException {
String input = FileUtils.readFileToString(new File("input.txt"));
System.out.println(input);
Pattern p = Pattern.compile("(program|function|process).*?\\{(.*?)\\}\n+(program|function|process)", Pattern.DOTALL);
Matcher m = p.matcher(input);
while(m.find()) {
System.out.println(m.group(1));
}
}
}
任何人都能说出我没有做对的事情?
我已经在Javascript中测试了正则表达式,但它确实有效。请参阅here。
答案 0 :(得分:1)
试
Pattern p = Pattern.compile("\\{(.*?)\\}(?!\\s*\\})\\s*", Pattern.DOTALL);
Matcher m = p.matcher(input);
while (m.find()) {
System.out.println(m.group(1));
}
输出
int x = 10;
tuple date {
int day;
int month;
int year;
}
int y = 20;
...
more code;
我认为这样会更可靠
for (int i = 0, j = 0, n = 0; i < input.length(); i++) {
char c = input.charAt(i);
if (c == '{') {
if (++n == 1) {
j = i;
}
} else if (c == '}' && --n == 0) {
System.out.println(input.substring(j + 1, i));
}
}
答案 1 :(得分:0)
试试这个:
Pattern p = Pattern.compile("(program|function|process).*?(\\{.*?\\})\\s*", Pattern.DOTALL);
Matcher m = p.matcher(input);
while(m.find()) {
System.out.println(m.group(2));
}