Question

我正在尝试使用openfiledialog选择我选择的图像区域我想要选择的区域是x，y坐标为5,5的16x16 选择后，我想将16x16图像绘制到坐标0,0

处的另一个pictureBox中

这是我已经获得的代码，但我无法选择原始图像的正确部分，有人建议为什么它不起作用？

DialogResult result = openFileDialog1.ShowDialog();
if (result == DialogResult.OK) // Test result.
{
    Image origImage = Image.FromFile(openFileDialog1.FileName);
    pictureBoxSkin.Image = origImage;
    lblOriginalFilename.Text = openFileDialog1.SafeFileName;

    System.Drawing.Bitmap bmp = new Bitmap(16, 16);
    Graphics g3 = Graphics.FromImage(bmp);
    g3.DrawImageUnscaled(origImage, 0, 0, 16, 16);

    Graphics g2 = pictureBoxNew.CreateGraphics();
    g2.DrawImageUnscaled(bmp, 0, 0, 16, 16);
}

Answer 1

要选择正确的部分，只需替换：

g3.DrawImageUnscaled(origImage, 0, 0, 16, 16);

与

g3.DrawImageUnscaled(origImage, -5, -5, 16, 16);

Answer 2

替换这个：

Graphics g2 = pictureBoxNew.CreateGraphics();
g2.DrawImageUnscaled(bmp, 0, 0, 16, 16);

用这个：

pictureBoxNew.Image = bmp;

你没事。

完整代码：

DialogResult result = openFileDialog1.ShowDialog();
if (result == DialogResult.OK) // Test result.
{
    Image origImage = Image.FromFile(openFileDialog1.FileName);
    pictureBoxSkin.Image = origImage;
    lblOriginalFilename.Text = openFileDialog1.SafeFileName;

    System.Drawing.Bitmap bmp = new Bitmap(16, 16);
    Graphics g3 = Graphics.FromImage(bmp);
    g3.DrawImageUnscaled(origImage, 0, 0, 16, 16);

    pictureBoxNew.Image = bmp;
    //Graphics g2 = pictureBoxNew.CreateGraphics();
    //g2.DrawImageUnscaled(bmp, 0, 0, 16, 16);
}

当您在Paint事件之外的任何地方绘制某些内容时，只要控件需要再次绘制（即从最小化状态恢复，另一个窗口经过时），它将被删除你的窗口，或者你调用Refresh方法。因此，将控件的绘图代码放在Paint事件中，或者让控件管理图像的绘制（在这种情况下，将Image分配给PictureBox控件。 / p>

选择图像区域

2 个答案: