是否可以在创建套接字对象后设置它的highWaterMark:
var http = require('http');
var server = http.createServer();
server.on('upgrade', function(req, socket, head) {
socket.on('data', function(chunk) {
var frame = new WebSocketFrame(chunk);
// skip invalid frames
if (!frame.isValid()) return;
// if the length in the head is unequal to the chunk
// node has maybe split it
if (chunk.length != WebSocketFrame.getLength()) {
socket.once('data', listenOnMissingChunks);
});
});
});
function listenOnMissingChunks(chunk, frame) {
frame.addChunkToPayload(chunk);
if (WebSocketFrame.getLength()) {
// if still corrupted listen once more
} else {
// else proceed
}
}
上面的代码示例不起作用。但是我该怎么做呢?
进一步解释: 当我收到大型WebSocket框架时,它们会分成多个数据事件。这使得解析帧变得困难,因为我不知道这是否是分裂或损坏的帧。
答案 0 :(得分:9)
我认为你误解了TCP套接字的本质。尽管TCP通过IP数据包发送数据,但TCP 不数据包协议。 TCP套接字只是数据的流。因此,将data
事件视为逻辑消息是不正确的。换句话说,一端的一个socket.write
不等于另一端的data
个事件。
对套接字的单次写入没有将1:1映射到单个data
事件的原因有很多:
data
事件(如您的应用程序所示)。因此,单个data
事件可能包含多条消息,单条消息或仅包含部分消息。
为了正确处理通过流发送的邮件,您必须buffer incoming data,直到收到完整邮件。
var net = require('net');
var max = 1024 * 1024 // 1 MB, the maximum amount of data that we will buffer (prevent a bad server from crashing us by filling up RAM)
, allocate = 4096; // how much memory to allocate at once, 4 kB (there's no point in wasting 1 MB of RAM to buffer a few bytes)
, buffer=new Buffer(allocate) // create a new buffer that allocates 4 kB to start
, nread=0 // how many bytes we've buffered so far
, nproc=0 // how many bytes in the buffer we've processed (to avoid looping over the entire buffer every time data is received)
, client = net.connect({host:'example.com', port: 8124}); // connect to the server
client.on('data', function(chunk) {
if (nread + chunk.length > buffer.length) { // if the buffer is too small to hold the data
var need = Math.min(chunk.length, allocate); // allocate at least 4kB
if (nread + need > max) throw new Error('Buffer overflow'); // uh-oh, we're all full - TODO you'll want to handle this more gracefully
var newbuf = new Buffer(buffer.length + need); // because Buffers can't be resized, we must allocate a new one
buffer.copy(newbuf); // and copy the old one's data to the new one
buffer = newbuf; // the old, small buffer will be garbage collected
}
chunk.copy(buffer, nread); // copy the received chunk of data into the buffer
nread += chunk.length; // add this chunk's length to the total number of bytes buffered
pump(); // look at the buffer to see if we've received enough data to act
});
client.on('end', function() {
// handle disconnect
});
client.on('error', function(err) {
// handle errors
});
function find(byte) { // look for a specific byte in the buffer
for (var i = nproc; i < nread; i++) { // look through the buffer, starting from where we left off last time
if (buffer.readUInt8(i, true) == byte) { // we've found one
return i;
}
}
}
function slice(bytes) { // discard bytes from the beginning of a buffer
buffer = buffer.slice(bytes); // slice off the bytes
nread -= bytes; // note that we've removed bytes
nproc = 0; // and reset the processed bytes counter
}
function pump() {
var pos; // position of a NULL character
while ((pos = find(0x00)) >= 0) { // keep going while there's a NULL (0x00) somewhere in the buffer
if (pos == 0) { // if there's more than one NULL in a row, the buffer will now start with a NULL
slice(1); // discard it
continue; // so that the next iteration will start with data
}
process(buffer.slice(0,pos)); // hand off the message
slice(pos+1); // and slice the processed data off the buffer
}
}
function process(msg) { // here's where we do something with a message
if (msg.length > 0) { // ignore empty messages
// here's where you have to decide what to do with the data you've received
// experiment with the protocol
}
}
答案 1 :(得分:0)
你不需要。传入的数据几乎肯定会分成两个或多个读取:这是TCP的本质,你无能为力。摆弄晦涩的套接字参数肯定不会改变它。数据将被点亮,但肯定不会被破坏。只需将套接字视为它是一个字节流。