Question

您好我正在处理一个简单的表单。表单提交正常但如果我刷新页面则重新提交数据。似乎表单在提交后持有数据，我假设自提交后请求方法发布。问题是提交清除Django表单后的最佳方法。提交后，表单变量不应再保留值。感谢

def testimonials(request, template_name="testimonials.html"):
reviews = Reviews.objects.all()
if request.method == 'POST':
    form = forms.ReviewsForm(data = request.POST)
    # create a new item

    if form.is_valid(): # All validation rules pass
        # Process the data in form.cleaned_data
        # ...
        if form.is_valid():
            nameIn = form.cleaned_data['name']
            reviewIn = form.cleaned_data['review']
            newReview = Reviews(name = nameIn, review = reviewIn)
            newReview.save()
            return render_to_response(template_name, locals(), context_instance=RequestContext(request))

else:
    # This the the first page load, display a blank form
    form = forms.ReviewsForm()

    return render_to_response(template_name, locals(), context_instance=RequestContext(request))

Answer 1

使用reverse而不是render to response

 if form.is_valid():
        nameIn = form.cleaned_data['name']
        reviewIn = form.cleaned_data['review']
        newReview = Reviews(name = nameIn, review = reviewIn)
        newReview.save()
        return HttpResponseRedirect(reverse('app_name:url'))

Answer 2

通常，您会在处理表单/ POST请求后发出重定向（这是常见的Web开发实践，以避免您提到的重新提交问题）。因此，您可以像render_to_response一样发布HttpResponseRedirect而不是if form.is_valid(): # Process form as desired here # Simple example; use reverse() to avoid hard-coding URLs return HttpResponseRedirect('/success/')：

{{1}}

查看using a form in view以获取通常如何处理表单的框架。

Answer 3

您还可以使用“重定向”快捷方式：

from django.shortcuts import redirect

...
return redirect(newReview)

这假设您在评论模型中定义了get_absolute_url。

有关详细信息，请参阅the docs。

Django表单再次提交刷新

3 个答案: