我正在尝试使用factory_boy测试两个Django模型之间的多对多关系。 factory_boy文档似乎没有讨论这个问题,我无法弄清楚我做错了什么。当我运行第一个测试时,我得到错误“AttributeError:'Pizza'对象没有属性'顶部'”。第二次测试我得到了类似的错误。
当我在调试器中运行测试时,我可以看到'toppings'对象,但它不知道如何从中获取名称。我是否正确定义了PizzaFactory的_prepare方法?当你有多对多的关系时,如何从另一个表中访问一个表中的名称?
感谢。
from django.db import models
class Topping(models.Model):
name = models.CharField(max_length=50)
def __unicode__(self):
return self.name
class Pizza(models.Model):
name = models.CharField(max_length=100)
toppings = models.ManyToManyField(Topping)
def __unicode__(self):
return self.name
import factory
from models import Topping, Pizza
class ToppingFactory(factory.Factory):
name = 'mushrooms'
class PizzaFactory(factory.Factory):
name = 'Vegetarian'
@classmethod
def _prepare(cls, create, **kwargs):
topping = ToppingFactory()
pizza = super(PizzaFactory, cls)._prepare(create, **kwargs)
pizza.toppings.add(topping)
return pizza
from django.test import TestCase
import factory
from app.models import Topping, Pizza
from app.factories import ToppingFactory, PizzaFactory
class FactoryTestCase(TestCase):
def test_pizza_has_mushrooms(self):
pizza = PizzaFactory()
self.assertTrue(pizza.topping.name, 'mushrooms')
def test_mushrooms_on_pizza(self):
topping = ToppingFactory()
self.assertTrue(topping.pizza.name, 'Vegetarian')
答案 0 :(得分:16)
我相信您需要使用@factory.post_generation
装饰器:
class PizzaFactory(factory.Factory):
name = 'Vegetarian'
@factory.post_generation
def toppings(self, create, extracted, **kwargs):
if not create:
# Simple build, do nothing.
return
if extracted:
# A list of groups were passed in, use them
for topping in extracted:
self.toppings.add(topping)
然后你会在tests.py pizza = PizzaFactory.create(toppings=(topping1, topping2, tooping3))
来自https://factoryboy.readthedocs.org/en/latest/recipes.html。
答案 1 :(得分:4)
只需使用调音台:
from mixer.backend.django import mixer
# Generate toppings randomly
pizza = mixer.blend(Pizza, toppings=mixer.RANDOM)
# Set toppings
toppings = mixer.cycle(3).blend(Topping)
pizza = mixer.blend(Pizza, toppings=toppings)
# Generate toppings with name=tomato
pizze = mixer.blend(Pizza, toppings__name='tomato')
简单,可配置,更快,无模式,声明,您可以在某些测试中获得所需的内容。