Question

所以，我的应用程序中有一个图层将一种类型的object映射到另一种类型。考虑ViewModel来建模映射类型。 ViewModel可能具有不同名称或模型中不存在的属性。反之亦然。

我想测试我的映射层，比较分配，但也允许我为不同的属性提供一些排序边缘案例处理。理想情况下，如果未检查ViewModel中的所有属性，则测试将失败。

有人知道这样的野兽是否已经存在？

public class CustomerViewModel
{
     // This is the same as CustomerModel.CustomerName, but the names differ
     public string Name { get; set; }
     public int ID { get; set; }
}

public class CustomerModel
{
     public string CustomerName { get; set; }
     public int ID { get; set; }
}

// Would auto test the properties that match automatically.  Additionaltest test for non matching.  Fails if all properties aren't tested
Assert.CompareObjects(customerViewModelInstance, customerModelInstance)
     .AdditionalTest("Name", "CustomerName")
     .AdditionalComplexText((viewModel, model) =>
           {
                // do some sort of a compare of complex objects.  Maybe the viewmodel has address fields, address1, address2 while the Model has an Address object with those fields.
           });

这背后的驱动力是必须在代码中手动断言每个属性的艰巨任务。

Answer 1

您需要覆盖.Equals()，以便与properties进行比较，然后使用

Assert.AreEqual Method (Object, Object)。请参阅以下内容：

Compare equality between two objects in NUnit

您可能希望在模型中实现这样的东西。

// useful class
public class MyStuff 
{
    public int Id { get; set; }
    public string Name { get; set; }
    public int MyValue { get; set; }

    public override int GetHashCode()
    {
        return Id;
    }

    public override bool Equals(object obj)
    {
        if (ReferenceEquals(this, obj)) return true;
        if (obj.GetType() != typeof (MyStuff)) return false;

        var other = obj as MyStuff;

        return (other.Id == Id
            && other.MyValue == MyValue
            && other.Equals(other.Name, Name));
        // use .Equals() here to compare objects; == for Value types

        // alternative weak Equals() for value objects:
        // return (other.MyValue == MyValue && other.Equals(other.Name, Name) );
    }
}

修改回想起来，我已经决定在viewmodel和model中复制属性可能是一个糟糕的模式，这也是你遇到很多测试问题的部分原因。相反，您应该允许ViewModel包装您的模型。

public class CustomerViewModel { // This is the same as CustomerModel.CustomerName, but the names differ public CustomerModel CustomerModel { get; set; } pubiic CustomerViewModel() { CustomerModel = new CustomerModel(); } } public class CustomerModel { public string CustomerName { get; set; } public int ID { get; set; } }

此时，测试它要容易得多，因为您拥有的包装模型可以使用.Equals覆盖模式与同一模型的新副本进行比较。在一天结束时，我只是不认为尝试提出一个“将任何模型与任何模型进行比较”的灵丹妙药是一个好主意，也不实用。

断言2个对象是相等的

1 个答案: