Question

我有这种XML结构：

<?xml version="1.0" encoding="UTF-8"?>
<kml xmlns="http://www.opengis.net/kml/2.2">
  <Document>
    <name>My Work</name>
    <Placemark>
      <name>Main Building</name>
      <Polygon>
        <extrude>1</extrude>
        <altitudeMode>relativeToGround</altitudeMode>
        <outerBoundaryIs>
          <LinearRing>
            <coordinates>
            </coordinates>
          </LinearRing>
        </outerBoundaryIs>
      </Polygon>
    </Placemark>

    <Placemark>
      <name>Office 1</name>
      <Polygon>
        <extrude>1</extrude>
        <altitudeMode>relativeToGround</altitudeMode>
        <outerBoundaryIs>
          <LinearRing>
            <coordinates>
            </coordinates>
          </LinearRing>
        </outerBoundaryIs>
      </Polygon>
    </Placemark>
  </Document>
</kml>

这继续......

我需要为每个建筑物选择建筑物“名称”并将其存储在列表中。我写了这段代码：

using System;
using System.Linq;
using System.Xml;
using System.Xml.Linq;
using System.Collections.Generic;

namespace dsdsdsds
{
    public class Building
    {
        public string BuildingName { get; set; }
    }

    class MainClass
    {
        public static void Main(string[] args)
        {
            List<Building> buildingNames = 
                (from e in XDocument.Load("buildings.kml").Root
                                    .Elements("Document")
                 select new Building
                 {
                     BuildingName = (string)e.Element("name")
                 }).ToList();

            foreach (var e in buildingNames)
            {
                Console.WriteLine(e);
            }
        }
    }
}

然而，它似乎不想输出任何东西，我无法找出我出错的地方。有谁可以帮助我？

谢谢

Answer 1

您忘记了xml中声明的命名空间：

var xdoc = XDocument.Load("buildings.kml");
XNamespace kml = "http://www.opengis.net/kml/2.2";
var buildings = xdoc.Root.Elements(kml + "Document")
                    .Select(d => new Building {
                        BuildingName = (string)d.Element(kml + "name")
                    }).ToList();

Answer 2

XDocument xDocument = XDocument.Load("buildings.kml");
XNamespace xNameSpace = "http://www.opengis.net/kml/2.2";

var names = from o in xDocument.Descendants(xNameSpace+"name")
            select o.Value;

我认为这是最简单的方法;不要忘记在查询元素之前添加命名空间。

Answer 3

从我所看到的，你试图遍历“文档” - 元素并选择它们的名字。相反，您可能希望更进一步，进入Placemark -elements，即

XDocument.Load("buildings.kml").Element("Document").Elements("Placemark")
                    select new Building
                    {
                        BuildingName = e.Element("name").Value
                    }).ToList();

使用LINQ从XML文件中选择元素

3 个答案: