Question

当对我的语料库进行单词频率计数时，结果似乎无法进行（不是我感觉最频繁的单词，频率计数只有一两个），有些结果显示“超过\ xe2”和' \ X-AD”。有人可以帮忙吗？

def toptenwords(mycorpus):
  mywords = mycorpus.words()
  nocapitals = [word.lower() for word in mywords] 
  filtered = [word for word in nocapitals if word not in stoplist]
  nopunctuation= [s.translate(None, string.punctuation) for s in filtered] 
  woordcounter = {}
     for word in nopunctuation:
        if word in wordcounter:
          woordcounter[word] += 1
        else:
          woordcounter[word] = 1
    frequentwords = sorted(wordcounter.iteritems(), key = itemgetter(1), reverse = True)
    top10 = frequentwords[:10]
    woord1 = frequentwords[1]
    woord2 = frequentwords[2]
    woord3 = frequentwords[3]
    woord4 = frequentwords[4]
    woord5 = frequentwords[5]
    woord6 = frequentwords[6]
    woord7 = frequentwords[7]
    woord8 = frequentwords[8]
    woord9 = frequentwords[9]
    woord10 = frequentwords[10]
    print "De 10 meest frequente woorden zijn: ", woord1, ",", woord2, ",", woord3, ",",    woord4, ",", woord5, ",", woord6, ",", woord7, ",", woord8, ",", woord9, "en", woord10

代码最初是荷兰语，这是非翻译代码：

def toptienwoorden(mycorpus):
   woorden = mycorpus.words()
   zonderhoofdletters = [word.lower() for word in woorden] 
   gefiltered = [word for word in zonderhoofdletters if word not in stoplijst] 
   geenleestekens = [s.translate(None, string.punctuation) for s in gefiltered] 
   woordteller = {}
   for word in geenleestekens:
      if word in woordteller:
         woordteller[word] += 1
      else:
         woordteller[word] = 1
  frequentewoorden = sorted(woordteller.iteritems(), key = itemgetter(1), reverse = True)
  top10 = frequentewoorden[:10]
  woord1 = frequentewoorden[1]
  woord2 = frequentewoorden[2]
  woord3 = frequentewoorden[3]
  woord4 = frequentewoorden[4]
  woord5 = frequentewoorden[5]
  woord6 = frequentewoorden[6]
  woord7 = frequentewoorden[7]
  woord8 = frequentewoorden[8]
  woord9 = frequentewoorden[9]
  woord10 = frequentewoorden[10]
  print "De 10 meest frequente woorden zijn: ", woord1, ",", woord2, ",", woord3, ",",    woord4, ",", woord5, ",", woord6, ",", woord7, ",", woord8, ",", woord9, "en", woord10

Answer 1

使用collections.Counter。它非常适合计算（可散布）项目的频率，并且它有一个most_common方法，可以返回前十个最常用的项目，而无需您自己编写逻辑代码：

import string
import collections


def topNwords(mywords, N = 10, stoplist = set(), filtered = set()):
    # mywords = mycorpus.words()
    nocapitals = [word.lower() for word in mywords]
    filtered = [word for word in nocapitals if word not in stoplist]
    nopunctuation = [s.translate(None, string.punctuation) for s in filtered]
    woordcounter = collections.Counter(nopunctuation)
    top_ten = [word for word, freq in woordcounter.most_common(N)]
    return top_ten


top_ten = topNwords('This is a test. It is only a test. In case of a real emergency'.split(), N = 10)
print("De 10 meest frequente woorden zijn: {w}".format(w = ', '.join(top_ten)))

字频计算奇怪的结果

1 个答案: