Question

 namespace PalleTech
 {          
     public class Parent
        {
            private int test = 123;
            public virtual int TestProperty
            {
                // Notice the accessor accessibility level.
                 set {
                    test = value;
                }

                // No access modifier is used here.
               protected get { return test; }
            }
        }
        public class Kid : Parent
        {
            private int test1 = 123;
            public override int TestProperty
            {
                // Use the same accessibility level as in the overridden accessor.
                 set { test1 = value / 123; }

                // Cannot use access modifier here.
               protected get { return 0; }
            }
        }
        public class Demo:Kid
        {
            public static void Main()
            {
                Kid k = new Kid();
                Console.Write(k.TestProperty);

            }
        }
    }

错误1无法通过“PalleTech.Kid”类型的限定符访问受保护的成员“PalleTech.Parent.TestProperty”;限定符必须是'PalleTech.Demo'类型（或从中派生出来）

Answer 1

From MSDN Article “只有通过派生类类型进行访问时，才能在派生类中访问基类的受保护成员。”

在这里，您将通过其实例访问Kid的受保护的setter。您必须创建Demo类的实例并通过它进行访问。

Answer 2

TestProperty类中Kid的getter受到保护，这意味着如果您编写一个派生自Kid类的类，则可以访问TestProperty;如果您创建Kid类的实例，则无法访问它。

您可以通过从两个类的setter中删除protected来更改行为;

public class Parent
{
    private int test = 123;
    public virtual int TestProperty
    {
        // Notice the accessor accessibility level.
        set
        {
            test = value;
        }

        // No access modifier is used here.
        get { return test; }
    }
}
public class Kid : Parent
{
    private int test1 = 123;
    public override int TestProperty
    {
        // Use the same accessibility level as in the overridden accessor.
        set { test1 = value / 123; }

        // Cannot use access modifier here.
        get { return 0; }
    }
}

Answer 3

您必须将评估员设置为受保护。 getter / setter的访问修饰符不能比属性本身更少。

尝试访问派生类中基类属性的受保护访问器时获取错误

3 个答案: