Question

我对这种情况有疑问，如何通过Array存储字符串？这是我的代码

<?php
$octets = array($_POST["oct1"],$_POST["oct2"],$_POST["oct3"],$_POST["oct4"]);
$octlenfnl = count($octets) - 1;
$binoctstr = 0 ;
if($_POST["oct1"] <= 255 && $_POST["oct1"] <= 255 && $_POST["oct1"] <= 255 && $_POST["oct1"] <= 255)
{
    for($i=0;$i<=$octlenfnl;$i++){
        echo str_pad(decbin($octets[$i]), 8, '0', STR_PAD_LEFT) , "&nbsp";
    }
}
else
{
    echo "Invalid IP!";
}

?>

它将输入的IP输出到二进制八位字节，就像这个11111111 0001000 10010101 10010101一样，它们在八位字节之间有空格，我如何拆分它们并将其存储到全局可访问的数组中？

由于

Answer 1

您可以使用$arr=explode(' ', "11111111 0001000 10010101 10010101");

Answer 2

而不是回应你的结果将它们存储到类似这样的数组

<?php
$octets = array($_POST["oct1"],$_POST["oct2"],$_POST["oct3"],$_POST["oct4"]);
$octlenfnl = count($octets) - 1;
$binoctstr = 0 ;
$binaryarray = array();
if($_POST["oct1"] <= 255 && $_POST["oct1"] <= 255 && $_POST["oct1"] <= 255 && $_POST["oct1"] <= 255)
{
  for($i=0;$i<=$octlenfnl;$i++){
      $binaryarray[] = str_pad(decbin($octets[$i]), 8, '0', STR_PAD_LEFT);
  }
}
    else
    {
        echo "Invalid IP!";
    }

//to echo out your results you can do this as a comma separated string
echo implode(",",$binaryarray);
//or if you wish to access a specific segment you can do this where $key is the array element you want
echo $binaryarray[$key];  

?>

更新简化编码的编辑

你可以稍微简化一下我认为这样的代码，除非你创建第二个数组并只是操纵你现有的数组。除非你需要任何初始数组，否则这应该可以正常工作

<?php
$octets = array($_POST["oct1"],$_POST["oct2"],$_POST["oct3"],$_POST["oct4"]);
$binoctstr = 0 ;
if($_POST["oct1"] <= 255 && $_POST["oct1"] <= 255 && $_POST["oct1"] <= 255 && $_POST["oct1"] <= 255)
{
  for($i=0;$i<=count($octets);$i++){
      $octets [$i] = str_pad(decbin($octets[$i]), 8, '0', STR_PAD_LEFT);
  }
}
    else
    {
        echo "Invalid IP!";
    }

//to echo out your results you can do this as a comma separated string
echo implode(",",$octets );
//or if you wish to access a specific segment you can do this where $key is the array element you want
echo $octets[$key];  

?>

Answer 3

使用此

$resultAsArray = explode(" ", $binaryOctets);

PHP：通过数组存储字符串

3 个答案: