我正在尝试编写二叉树,并且add方法不断覆盖树的根。我有两个方法,一个递归的add方法,它接受一个String和一个Node,然后是一个简单调用递归方法的常规add方法。任何帮助将不胜感激。
public Node recAdd(String event , Node tNode ){
//tNode -> tree node
if (tNode == null){
// Addition place found
root = new Node(event);
System.out.println("added root");
}
else if (tNode.event.compareTo(event) <= 0){
tNode.setLeft(recAdd(event, tNode.getLeft()));
// System.out.println("added left");// Add in left subtree
}
else{
tNode.setRight(recAdd(event, tNode.getRight()));
// System.out.println("added right");
}// Add in right subtree
return tNode;
}
////////////////////////////////////////////// < / p>
public void add(String event){
if(root != null){
System.out.println("The root currently is " + root.event );
}
recAdd(event , root);
}
我的节点类如下
public class Node {
Node left;
Node right;
String event;
Node(String event){
this.event = event;
this.left = null;
this.right = null;
}
public void setEvent(String event){
this.event = event;
}
public void setLeft(Node left){
this.left = left;
}
public void setRight(Node right){
this.right = right;
}
public String getEvent(){
return event;
}
public Node getLeft(){
return left;
}
public Node getRight(){
return right;
}
}
答案 0 :(得分:1)
每当找到插入当前节点的位置时,您将替换根节点:
public Node recAdd(String event, Node tNode) {
//tNode -> tree node
if (tNode == null) {
// Addition place found
root = new Node(event); // Problem is RIGHT HERE
System.out.println("added root");
}
//...
}
答案 1 :(得分:0)
发生的事情是您递归搜索树,直到到达尚未分配的节点(即null
)。此时,您将覆盖root而不是创建新节点。
例如:
root
/ \
node null <- You want to assign this node, not overwrite root
/ \
null null
要做到这一点:
public Node recAdd(String event , Node tNode ){
if (tNode == null){
tNode = new Node(event); // <--- Don't overwrite root
}
else if (tNode.event.compareTo(event) <= 0){
tNode.setLeft(recAdd(event, tNode.getLeft()));
}
else{
tNode.setRight(recAdd(event, tNode.getRight()));
}
return tNode;
}
您还需要修改add()
功能:
public void add(String event){
root = recAdd(event , root); // <-----Reassign root
}