我有一个spring mvc应用程序并使用mockito进行单元测试。当我运行单元测试时,我一直得到空指针异常。 :(
请在下面找到我的单元测试所基于的方法:
@Controller
public class LogInController {
@Autowired
private MessageSource messageSource;
@RequestMapping(method = RequestMethod.POST, value = "/login")
public ModelAndView validateViewLogin(@ModelAttribute Person person,
BindingResult result, HttpServletRequest request) {
ModelAndView mav = new ModelAndView();
String userName = person.getFirstName();
String password = person.getPassword();
boolean isUserValid = false;
if (userName != null && password != null) {
isUserValid = userManagerService.validateUserLogin(userName,password);
}
if (!isUserValid) {
mav.addObject("failLog",messageSource.getMessage("login.user.fail", new String[] {" ", "" }, request.getLocale()));
mav.addObject("isUserValid", false);
mav.setViewName("login");
return mav;
}
mav.addObject("isUserValid", isUserValid);
mav.setViewName("home");
return mav;
}
请在下面找我的单元测试:
@Test
public void validateViewLogin_NotValidLogin_returnsLoginPage() {
MockHttpServletRequest request = new MockHttpServletRequest();
Person person = new Person();
person.setFirstName("John");
person.setPassword("123");
isUserValid = false;
LogInController controller = new LogInController();
// Inject mock user service into controller
UserManagerService mockUserService = mock(UserManagerService.class);
controller.setUserManagerService(mockUserService);
// Configure mock user service to accept the person
when(mockUserService.validateUserLogin("John", "123")).thenReturn(
isUserValid);
// Attempt the validation
ModelAndView mav = controller
.validateViewLogin(person, result, request);
// Check the result
assertEquals("login", mav.getViewName());
}
当我运行上面的单元测试时,请找到下面的堆栈跟踪错误消息:
java.lang.NullPointerException
at com.gemstone.presentation.LogInController.validateViewLogin(LogInController.java:99)
at com.gemstone.presentation.LogInControllerTest.validateViewLogin_NotValidLogin_returnsLoginPage(LogInControllerTest.java:79)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
at java.lang.reflect.Method.invoke(Unknown Source)
at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java:44)
at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:15)
at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:41)
at org.junit.internal.runners.statements.InvokeMethod.evaluate(InvokeMethod.java:20)
at org.junit.runners.BlockJUnit4ClassRunner.runNotIgnored(BlockJUnit4ClassRunner.java:79)
at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:71)
at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:49)
at org.junit.runners.ParentRunner$3.run(ParentRunner.java:193)
at org.junit.runners.ParentRunner$1.schedule(ParentRunner.java:52)
at org.junit.runners.ParentRunner.runChildren(ParentRunner.java:191)
at org.junit.runners.ParentRunner.access$000(ParentRunner.java:42)
at org.junit.runners.ParentRunner$2.evaluate(ParentRunner.java:184)
at org.junit.runners.ParentRunner.run(ParentRunner.java:236)
at org.eclipse.jdt.internal.junit4.runner.JUnit4TestReference.run(JUnit4TestReference.java:50)
at org.eclipse.jdt.internal.junit.runner.TestExecution.run(TestExecution.java:38)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:467)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:683)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.run(RemoteTestRunner.java:390)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.main(RemoteTestRunner.java:197)
基本上,如下所示的第99行根据堆栈跟踪返回null:
mav.addObject(
"failLog",
messageSource.getMessage("login.user.fail", new String[] {
" ", "" }, request.getLocale()));
为什么我在这条线上获得空指针的任何想法呢?但是当我运行我的应用程序时它工作正常并且我的页面上显示failLog消息。
提前感谢。
答案 0 :(得分:3)
我的猜测是你的messageSource为空。您正在嘲笑您的请求,但不是您的messageSource,并且您正在新建登录控制器,它不是由Spring注入的。
运行时会自动注入Spring。
编辑以澄清:
首先,您需要能够设置一些测试方法。您可以添加一个setter或构造函数来实现它,例如:
@Controller
public class LogInController {
@Autowired
private MessageSource messageSource;
public void setMessageSource(MessageSource ms){
this.messageSource = ms;
}
// ......
}
然后你的测试也需要改变:
@Test
public void validateViewLogin_NotValidLogin_returnsLoginPage() {
MockHttpServletRequest request = new MockHttpServletRequest();
Person person = new Person();
person.setFirstName("John");
person.setPassword("123");
isUserValid = false;
LogInController controller = new LogInController();
// Inject mock user service into controller
UserManagerService mockUserService = mock(UserManagerService.class);
/** ADDED **/
MessageSource ms = mock(MessageSource.class);
controller.setUserManagerService(mockUserService);
/** ADDED **/
controller.setMessageSource(ms);
// Configure mock user service to accept the person
when(mockUserService.validateUserLogin("John", "123")).thenReturn(
isUserValid);
/** ADDED **/
when(ms.getMessage("login.user.fail", new String[] {" ", "" }).thenReturn("message");
// Attempt the validation
ModelAndView mav = controller
.validateViewLogin(person, result, request);
// Check the result
assertEquals("login", mav.getViewName());
}
只需免费处理,所以请确保我没有任何拼写错误!从本质上讲,你像在使用UserManagerService时一样尝试MessageSource,它毕竟只是一个界面,并且可以完全相同的方式进行模拟。