Question

我有NSMutableArray NSDictionary这样的内容：

myArray (
    {
    chatins = 20;
    placeImageString = 244211112265925;
},
    {
    chatins = 5;
    placeImageString = 154909144575109;
},
    {
    chatins = 30;
    placeImageString = 193867280641162;
},
    {
    chatins = 13;
    placeImageString = 224627130902;
},

）

和NSMutableArray的另一个NSDictionary是这样的：

myArray2 
(
    {
    category = "Local business";
    distance = "0.1";
    name = "Mts India";
    placeImageString = 244211112265925;
},
    {
    category = "Local business";
    distance = "0.17";
    name = "Aegis Ltd";
    placeImageString = 154909144575109;
},
    {
    category = "Automobiles and parts";
    distance = "0.19";
    name = Autopsyche;
    placeImageString = 78480207511;
},
    {
    category = Company;
    distance = "0.19";
    name = "The Oberoi, Gurgaon";
    placeImageString = 121676041233945;
},

）

我想合并myArray和myArray2，以获得NSMutableArray NSDictionary placeImageString的结果，如下所示我的myArray2是匹配的关键字两个字典数组中的数据，如果在chatins中找不到密钥，则myArray3 ( { category = "Local business"; distance = "0.1"; name = "Mts India"; placeImageString = 244211112265925; chatins = 20; }, { category = "Local business"; distance = "0.17"; name = "Aegis Ltd"; placeImageString = 154909144575109; chatins = 5; }, { category = "Automobiles and parts"; distance = "0.19"; name = Autopsyche; placeImageString = 78480207511; chatins = 0; }, { category = Company; distance = "0.19"; name = "The Oberoi, Gurgaon"; placeImageString = 121676041233945; chatins = 0; }, )密钥的值应为0。

{{1}}

Answer 1

这里我有一个示例代码：

  NSMutableArray *array1 = [[NSMutableArray alloc] init];
  NSMutableArray *array2 = [[NSMutableArray alloc] init];


  NSMutableDictionary * dict = [[NSMutableDictionary alloc]
                                initWithObjects:[NSArray arrayWithObjects:@"1",@"ABC", nil]
                                forKeys:[NSArray arrayWithObjects:@"ID",@"NAME", nil]];
  [array1 addObject:dict];

  dict = nil;

  /*
   Same way added 2 more dictionaries to the same array - array1
   */

  NSLog(@"array1: %@", array1);


  dict = nil;

  dict = [[NSMutableDictionary alloc]
          initWithObjects:[NSArray arrayWithObjects:@"1",@"DEF", nil]
          forKeys:[NSArray arrayWithObjects:@"ID",@"ADDRESS", nil]];

  [array2 addObject:dict];

  dict = nil;

  /*
   Same way added 2 more dictionaries to the same array - array2
   */


  NSLog(@"array2: %@", array2);


  for (int index = 0; index < [array1 count]; index ++) {

    NSMutableDictionary *dict1 = [array1 objectAtIndex:index];

    for (NSMutableDictionary *dict2 in array2) {

      if ([[dict1 objectForKey:@"ID"] isEqualToString:
           [dict2 objectForKey:@"ID"]]) {

        [dict1 setObject:[dict2 objectForKey:@"ADDRESS"] forKey:@"ADDRESS"];
      }
    }
  }

现在最后如果您使用 array1 进行检查，则在所有这些字典中还会添加一个密钥（ ADDRESS ）。

希望得到这个帮助。

-Mrunal

Answer 2

1. Create a new empty NSMutableArray newArray
2. Loop through all NSDictionaries of myArray2

    a. Copy the current NSDictionary to a new NSMutableDictionary newDict
    b. Loop through myArray1
        b1. if myArray1.dict.placeImageString == newDict.placeImageString
            - Add myArray1.dict.chatins to newDict
            - break out of loop
    c. add newDict to newArray

合并包含NSDictionarys的NSArrays

2 个答案: