Question

我的应用程序无法创建简单的表。请参阅以下代码，

DatabaseHandler.java

public class DatabaseHandler extends SQLiteOpenHelper {

private static final int DB_VERSION = 1;
private static final String DB_NAME = "PASSENGER_INFO_DB";
private static final String TABLE_NAME = "PASSENGER_INFO";
private static final String TABLE_COLUMN_SEAT_NO = "SEAT_NO";
private static final String TABLE_COLUMN_NAME = "NAME";
private static final String TABLE_COLUMN_AGE = "AGE";
private static final String TABLE_COLUMN_GENDER = "GENDER";
private static final String TABLE_COLUMN_FOOD_PREF = "FOOD_PREF";

private static final String CREATE_PASSENGER_INFO_TABLE = "CREATE TABLE IF NOT EXISTS "
        + TABLE_NAME + " ( " + TABLE_COLUMN_SEAT_NO
        + " TEXT PRIMARY KEY, " + TABLE_COLUMN_NAME + " TEXT, "
        + TABLE_COLUMN_AGE + " INTEGER, " + TABLE_COLUMN_GENDER
        + " INTEGER, " + TABLE_COLUMN_FOOD_PREF + " TEXT" + ")";

public DatabaseHandler(Context context) {
    super(context, DB_NAME, null, DB_VERSION);
}

@Override
public void onCreate(SQLiteDatabase db) {
    db.execSQL(CREATE_PASSENGER_INFO_TABLE);
}
public void addPassengerInfo(PassengerInfo passInfo) {
    SQLiteDatabase addPass = this.getWritableDatabase();

    ContentValues values = new ContentValues();

    values.put(TABLE_COLUMN_SEAT_NO, passInfo.getM_seatNo());
    values.put(TABLE_COLUMN_NAME, passInfo.getM_name());
    values.put(TABLE_COLUMN_AGE, passInfo.getM_age());
    values.put(TABLE_COLUMN_GENDER, passInfo.getM_gender());
    values.put(TABLE_COLUMN_FOOD_PREF, passInfo.getM_foodPref());

    addPass.insert(TABLE_NAME, null, values);
    addPass.close();
}

MainActivity.java中的

DatabaseHandler dbhandler = new DatabaseHandler(this);
addSeat = "1A";
passName = "NA";
passAge = 0;
passGender = -1;
passFoodPref = "NA";
dbhandler.addPassengerInfo(new PassengerInfo(addSeat, passName, passAge, passGender, passFoodPref));

（PassengerInfo.class具有字段的getter和setter方法）

当我运行这个时，我在logcat中遇到以下错误，

01-23 19:09:18.311: I/Database(1303): sqlite returned: error code = 1, msg = table PASSENGER_INFO has no column named SEAT_NO
01-23 19:09:18.370: E/Database(1303): Error inserting FOOD_PREF=NA NAME=NA AGE=0 GENDER=-1 SEAT_NO=1A

我还通过adb shell检查了数据库中创建的表，没有名称为PASSENGER_INFO的表。请帮忙！

Answer 1

您在创建表

中最后遗漏了一个半字节

+ " TEXT" + ");";

Answer 2

“）之后的分号;”在查询和查询丢失。 P.s鼓励您将数据插入数据库的方式应该使用 Contentvalues

     ContentValues row = new ContentValues();
     row.put("SEAT_NO",tid);
     row.put("NAME", sid);
     row.put("AGE", rsubject);
     row.put("GENDER",rdescr);
     row.put("FOOD_PREF", day);


     long chk = db.insert("PASSENGER_INFO",null, row);

此外，正确的查询将是

  db.execSQL(" CREATE TABLE " + DATABASE_MARKSTABLE + " (" +
                "SEAT_NO" + " TEXT PRIMARY KEY, " +
                "NAME" + " TEXT NOT NULL, " +
                "AGE" + " INTEGER NOT NULL, " +
                "GENDER" + " INTEGER NOT NULL, " +
                "FOOD_PREF" + " TEXT);"
        );

Answer 3

我假设您创建的表格（PASSENGER_INFO）没有SEAT_NO列，以后再添加它。你需要做的是增加DB_VERSION并重新运行应用程序。什么会导致DatabaseHandler的onUpdate()运行。您没有显示该代码，但希望它会删除该表，然后调用onCreate()重新创建表（现在使用SEAT_NO列）。

旁注：我会将该表的主键更改为_id，就像你拥有它一样，你只能存储一个航班的座位......当然，设计是由你。

无法在android中创建表

3 个答案: