Question

假设我想在.txt文件中收集一些统计信息，如下所示：

misses 15
hit 18
misses 20
hit 31

我写了一个只打印每一行的bash脚本：

#!/bin/bash 
while read line           
do           
    echo $line 
done <t.txt

我现在想要的是：示例是伪代码：

read every line
   if first column is miss add the number to total misses
   if hits add the number to total hits

print total hits, and total misses in a file

我已经搜索过，这可以用awk完成。你能帮助用awk做这件事吗？

Answer 1

只需将您的算法翻译为bash：

#!/bin/bash 
while read what count ; do           
    case $what in
        (hit)    let total_h+=count ;;
        (misses) let total_m+=count ;;
        (*)      echo Invalid input >&2; exit ;;
    esac
done < t.txt
echo Hits: $total_h, Misses: $total_m

Answer 2

不需要任何bash gubbins，awk会做到这一切

awk 'BEGIN{ hits=0; misses=0; }/^hit/{ hits+=$NF}; /^misses/{misses=$NF}; END {print "Hits: " hits "\nMisses: " misses }' txtfile

这一个班轮的3个部分：

BEGIN{ hits=0; misses=0; }

在awk从txtfile读取任何行并初始化两个变量命中和未命中之前，只运行一次。

/^hits/{ hits+=$NF}; /^misses/{misses=$NF};

在每一行上运行，如果该行以命中开头，则最后一列被添加到hits变量，如果它以未命中开头，那么未命中变量将添加最后一列。

END {print "Hits: " hits "\nMisses: " misses' }

仅在处理完所有行后运行并打印出详细说明命中和未命中的消息。

Answer 3

awk '/misses/||/hit/{a[$1]+=$2}END{print "total hits",a["hit"],",and total misses",a["misses"]}' your_file

测试：

> cat temp
misses 15
hit 18
misses 20
hit 31
hait 31
> awk '/misses/||/hit/{a[$1]+=$2}END{print "total hits",a["hit"],",and total misses",a["misses"]}' temp
total hits 49 ,and total misses 35

Answer 4

declare misses=0 hit=0
while read var val; do
    let $var+=val
done < f.txt
echo "Misses: $misses"
echo "Hits: $hit"

使用bash从文件中读取数据并使用awk获取某些列的总和

4 个答案: