我有一个带有以下标记的xml文件：
<param>
<name>date</name>
<Value>20010202</Value>
</param>
我在文件中有很多这样的标签。我需要通过批处理读取此文件，并将date的值更新为name其中包含“date”的字符串。 我已经批量编写了一些代码来将日期（无论在完整文件中的哪个位置）替换为所需的字符串。我的代码如下：
for /f "tokens=1,* delims=]" %%K in ('"type "example.xml"|find /n /v """') do (
set "line=%%L"
if defined line (
call set "line=echo.%%line:20010202=desiredString%%"
for /f "delims=" %%C in ('"echo."%%line%%""') do %%~C
) else echo.
) >> "example.tmp"
但是我需要检查更换日期应该是name标签的值标签为“date”。 我想在for循环中执行检查，然后在当前行匹配时读取下一行。
如何读取for循环中的一行并检查批处理文件中是否有条件？
答案 0 :(得分：4)
我想您可以使用纯批次编写解决方案，但它可能会缓慢而脆弱。脆弱我的意思是XML可以以逻辑上等效的方式重新格式化，但却破坏了代码。 Batch可能是您可以用来操作XML的最差语言之一。
理想情况下，您应该使用明确设计用于处理XML的命令行工具。或者，您可以使用支持正则表达式搜索和替换的任何语言或工具。一些选项 - VBScript，JScript，gnu sed for Windows，Powershell ......列表继续。
我编写了一个混合批处理/ JScript REPL.BAT实用程序，它为批处理提供了一种简单的方法来执行正则表达式搜索和替换文本文件。它比任何纯批量解决方案都快得多，速度更快。
以下是使用我的REPL.BAT实用程序的简单解决方案：
@echo off
setlocal
set "file=example.xml"
set "oldDate=20010202"
set "newDate=20130123"
set "search=(<param>\s*<name>date</name>\s*<Value>)%oldDate%(</Value>\s*</param>)"
type "%file%"|repl "%search%" "$1%newDate%$2" m >"%file%.new"
move /y "%file%.new" "%file%" >nul
这是REPL.BAT实用程序。完整的文档嵌入在脚本中。
@if (@X)==(@Y) @end /* Harmless hybrid line that begins a JScript comment
::************ Documentation ***********
:::
:::REPL Search Replace [Options [SourceVar]]
:::REPL /?
:::
::: Performs a global search and replace operation on each line of input from
::: stdin and prints the result to stdout.
:::
::: Each parameter may be optionally enclosed by double quotes. The double
::: quotes are not considered part of the argument. The quotes are required
::: if the parameter contains a batch token delimiter like space, tab, comma,
::: semicolon. The quotes should also be used if the argument contains a
::: batch special character like &, |, etc. so that the special character
::: does not need to be escaped with ^.
:::
::: If called with a single argument of /? then prints help documentation
::: to stdout.
:::
::: Search - By default this is a case sensitive JScript (ECMA) regular
::: expression expressed as a string.
:::
::: JScript syntax documentation is available at
::: http://msdn.microsoft.com/en-us/library/ae5bf541(v=vs.80).aspx
:::
::: Replace - By default this is the string to be used as a replacement for
::: each found search expression. Full support is provided for
::: substituion patterns available to the JScript replace method.
::: A $ literal can be escaped as $$. An empty replacement string
::: must be represented as "".
:::
::: Replace substitution pattern syntax is documented at
::: http://msdn.microsoft.com/en-US/library/efy6s3e6(v=vs.80).aspx
:::
::: Options - An optional string of characters used to alter the behavior
::: of REPL. The option characters are case insensitive, and may
::: appear in any order.
:::
::: I - Makes the search case-insensitive.
:::
::: L - The Search is treated as a string literal instead of a
::: regular expression. Also, all $ found in Replace are
::: treated as $ literals.
:::
::: E - Search and Replace represent the name of environment
::: variables that contain the respective values. An undefined
::: variable is treated as an empty string.
:::
::: M - Multi-line mode. The entire contents of stdin is read and
::: processed in one pass instead of line by line. ^ anchors
::: the beginning of a line and $ anchors the end of a line.
:::
::: X - Enables extended substitution pattern syntax with support
::: for the following escape sequences:
:::
::: \\ - Backslash
::: \b - Backspace
::: \f - Formfeed
::: \n - Newline
::: \r - Carriage Return
::: \t - Horizontal Tab
::: \v - Vertical Tab
::: \xnn - Ascii (Latin 1) character expressed as 2 hex digits
::: \unnnn - Unicode character expressed as 4 hex digits
:::
::: Escape sequences are supported even when the L option is used.
:::
::: S - The source is read from an environment variable instead of
::: from stdin. The name of the source environment variable is
::: specified in the next argument after the option string.
:::
::************ Batch portion ***********
@echo off
if .%2 equ . (
if "%~1" equ "/?" (
findstr "^:::" "%~f0" | cscript //E:JScript //nologo "%~f0" "^:::" ""
exit /b 0
) else (
call :err "Insufficient arguments"
exit /b 1
)
)
echo(%~3|findstr /i "[^SMILEX]" >nul && (
call :err "Invalid option(s)"
exit /b 1
)
cscript //E:JScript //nologo "%~f0" %*
exit /b 0
:err
>&2 echo ERROR: %~1. Use REPL /? to get help.
exit /b
************* JScript portion **********/
var env=WScript.CreateObject("WScript.Shell").Environment("Process");
var args=WScript.Arguments;
var search=args.Item(0);
var replace=args.Item(1);
var options="g";
if (args.length>2) {
options+=args.Item(2).toLowerCase();
}
var multi=(options.indexOf("m")>=0);
var srcVar=(options.indexOf("s")>=0);
if (srcVar) {
options=options.replace(/s/g,"");
}
if (options.indexOf("e")>=0) {
options=options.replace(/e/g,"");
search=env(search);
replace=env(replace);
}
if (options.indexOf("l")>=0) {
options=options.replace(/l/g,"");
search=search.replace(/([.^$*+?()[{\\|])/g,"\\$1");
replace=replace.replace(/\$/g,"$$$$");
}
if (options.indexOf("x")>=0) {
options=options.replace(/x/g,"");
replace=replace.replace(/\\\\/g,"\\B");
replace=replace.replace(/\\b/g,"\b");
replace=replace.replace(/\\f/g,"\f");
replace=replace.replace(/\\n/g,"\n");
replace=replace.replace(/\\r/g,"\r");
replace=replace.replace(/\\t/g,"\t");
replace=replace.replace(/\\v/g,"\v");
replace=replace.replace(/\\x[0-9a-fA-F]{2}|\\u[0-9a-fA-F]{4}/g,
function($0,$1,$2){
return String.fromCharCode(parseInt("0x"+$0.substring(2)));
}
);
replace=replace.replace(/\\B/g,"\\");
}
var search=new RegExp(search,options);
if (srcVar) {
WScript.Stdout.Write(env(args.Item(3)).replace(search,replace));
} else {
while (!WScript.StdIn.AtEndOfStream) {
if (multi) {
WScript.Stdout.Write(WScript.StdIn.ReadAll().replace(search,replace));
} else {
WScript.Stdout.WriteLine(WScript.StdIn.ReadLine().replace(search,replace));
}
}
}
答案 1 :(得分：0)
虽然我们都知道Batch很慢，但我认为没有人知道在与其他解决方案进行比较时到底在多大程度上。下面有一个针对这个问题的纯批处理解决方案，我认为可以相当快。我可以请求您（或任何人）使用大型.xml文件测试此解决方案并获得比较时间吗？这些信息对我们所有人都有价值！
@echo off
setlocal EnableDelayedExpansion
set "file=example.xml"
set "oldDate=20010202"
set "newDate=20130123"
set lastLine=1
set line=
echo "<name>date</name>" >> "%file%"
< "%file%" (for /F "delims=:" %%a in ('findstr /N /C:"<name>date</name>" "%file%"') do (
if not defined line set /P line=
set /A lines=%%a-lastLine, lastLine+=lines+1
for /L %%i in (1,1,!lines!) do set /P "line=!line!" & echo/
set nextLine=
set /P nextLine=
if defined nextLine (
echo !line!
set "line=!nextLine:<Value>%oldDate%</Value>=<Value>%newDate%</Value>!"
)
)) > "%file%.new"
move /Y "%file%.new" "%file%"
请注意，之前的Batch程序错误地处理了文件中的空行。虽然这一点可以修复，但附加代码会降低程序的速度，所以我想首先了解原始代码与其他解决方案的比较。使用没有空行的.xml文件测试此程序。
安东尼奥