我使用这个优秀的论坛来教自己一些基本的xpath来查询.XML文件。我在这里得到了一个XML文件样本,我正在尝试使用Matlab导入XML文件中3个对象的[X,Y]坐标:
<!DOCTYPE plist PUBLIC "-//Apple//DTD PLIST 1.0//EN" "http://www.apple.com/DTDs/PropertyList-1.0.dtd">
<plist version="1.0">
<dict>
<key>ROI array</key>
<array>
<dict>
<key>Comments</key>
<string></string>
<key>Name</key>
<string>Unnamed</string>
<key>ROIPoints</key>
<array>
<string>{129.24051549947484, 263.66036033996352}</string>
<string>{114.61421850240453, 278.56760216125258}</string>
<string>{123.11826208150609, 289.73859978088149}</string>
<string>{125.11111111111111, 295.77777777777777}</string>
</array>
<key>Slice</key>
<integer>58</integer>
</dict>
<dict>
<key>Comments</key>
<string></string>
<key>Name</key>
<string>Unnamed</string>
<key>ROIPoints</key>
<array>
<string>{127.09352448499425, 261.31629753478774}</string>
<string>{112.50917389905675, 277.25509453185805}</string>
<string>{126.061969309213, 291.36980247863539}</string>
<string>{141.48499634778722, 292.16234398254164}</string>
<string>{149.71229126966222, 277.81281090148696}</string>
</array>
<key>Slice</key>
<integer>59</integer>
</dict>
<dict>
<key>Comments</key>
<string></string>
<key>Name</key>
<string>Unnamed</string>
<key>ROIPoints</key>
<array>
<string>{134.32833430087788, 258.21743274101027}</string>
<string>{117.0812182120107, 266.44891620048293}</string>
<string>{114.41427180087788, 292.20427203544386}</string>
<string>{128.80573603427632, 299.11905932792433}</string>
<string>{147.92307612216695, 299.11905932792433}</string>
<string>{152.73700281894429, 285.80526996024855}</string>
<string>{154.32626673495992, 268.51202655204543}</string>
</array>
<key>Slice</key>
<integer>60</integer>
</dict>
</array>
</dict>
</plist>
我已设法使用此Matlab代码导出所有坐标:
expression_2 = xpath.compile('plist/dict/array/dict/array/string');
nodeList_2 = expression_2.evaluate(docNode, XPathConstants.NODESET);
for i = 1:nodeList_2.getLength
node = nodeList_2.item(i-1);
coordinate_node{i} = char(node.getFirstChild.getNodeValue);
end
有没有人知道xpath查询,我可以计算每个对象中[X,Y]坐标的NUMBER个?即返回第一个对象的4个坐标,第二个坐标为5个坐标,第3个坐标为7个坐标?
谢谢, 吉姆
答案 0 :(得分:1)
我不熟悉你的matlab的XPath实现,但XPath确实有聚合函数,我在Java中使用它们:
http://www.w3.org/TR/xpath-functions/#func-count
请首先参阅有关此主题的matlab手册。你也可以在这个类似的问题中看一眼如何使用它。
How do I use XPath to count the number of nodes with a certain attribute
答案 1 :(得分:1)
你走在正确的轨道上。但是,问题在于您的代码以平面方式提取所有“字符串”节点,而忽略父“数组”节点。这样您无法分辨哪个坐标属于哪个对象。
如果你稍微修改你的代码以便它以分层方式遍历“数组”和“字符串”节点,它可以像你想要的那样工作:
%// Extract 'array' nodes
expr_array = xpath.compile('plist/dict/array/dict/array');
nodeList_array = expr_array.evaluate(docNode, XPathConstants.NODESET);
C = cell(nodeList_array.getLength, 1);
for k = 1:nodeList_array.getLength
%// Extract 'string' nodes
node_array = nodeList_array.item(k - 1);
expr_string = xpath.compile('string');
nodeList_string = expr_string.evaluate(node_array, XPathConstants.NODESET);
coordinates = zeros(nodeList_string.getLength, 2);
for m = 1:nodeList_string.getLength
node_string = nodeList_string.item(m - 1);
s = char(node_string.getFirstChild.getNodeValue); %// Extract string
coordinates(m, :) = str2num(s(2:end - 1)); %// Convert to numbers
end
C{k} = coordinates;
end
现在单元格数组C
包含所有坐标(顺便说一句,我将它们转换为数值,以便它们可以存储在矩阵中并轻松操作):
C{1} =
129.2405 263.6604
114.6142 278.5676
123.1183 289.7386
125.1111 295.7778
C{2} =
127.0935 261.3163
112.5092 277.2551
126.0620 291.3698
141.4850 292.1623
149.7123 277.8128
C{3} =
134.3283 258.2174
117.0812 266.4489
114.4143 292.2043
128.8057 299.1191
147.9231 299.1191
152.7370 285.8053
154.3263 268.5120
现在,如果您想要每个单元格(对象)中的坐标数量,只需执行以下操作:
cellfun(@(c)size(c, 1), C)
您将获得所需的结果:
ans=
4
5
7