如何选择不同的字符串？ （更轻松）

Question

我有String cat = "cat1, cat1, cat1, cat1, cat2, cat2, cat2, cat3";

我需要String cat = "cat1, cat2, cat3";

怎么做？

这是我的解决方案，但不是很好：

String[] words = cat.split(",");
Arrays.sort(words);
....

Answer 1

你可以试试这个 -

String cat = "cat1,cat1,cat1,cat1,cat2,cat2,cat2,cat3";
Set<String> set = new HashSet<String>(Arrays.asList(cat.split(",")));

Answer 2

尝试

String cat = "cat1, cat1, cat1, cat1, cat2, cat2, cat2, cat3";
String text = new TreeSet<String>(Arrays.asList(cat.split(", "))).toString();
String cats = text.substring(1, text.length()-1);
System.out.println(cats);

这将产生你需要的字符串。

cat1, cat2, cat3

Answer 3

这里：

//hash
HashSet<String> hs = new HashSet<String>();
String[] words = cat.split(",");
for(int i = 0;i < words.length; i++) hs.add(words[i]);

//dehash
StringBuilder builder = new StringBuilder();
Iterator it = hs.iterator();
while(it.hasNext())
{
    builder.append(it.next());
    builder.append(",");
}
String dehashed = builder.toString();