我有一些在canvas元素上绘制矩形的函数。绘制元素时,我希望能够通过拖动角来调整其大小。
var canvas = document.getElementById('canvas'),
ctx = canvas.getContext('2d'),
rect = {},
drag = false;
function init() {
canvas.addEventListener('mousedown', mouseDown, false);
canvas.addEventListener('mouseup', mouseUp, false);
canvas.addEventListener('mousemove', mouseMove, false);
}
function mouseDown(e) {
rect.startX = e.pageX - this.offsetLeft;
rect.startY = e.pageY - this.offsetTop;
drag = true;
}
function mouseUp() {
drag = false;
}
function mouseMove(e) {
if (drag) {
rect.w = (e.pageX - this.offsetLeft) - rect.startX;
rect.h = (e.pageY - this.offsetTop) - rect.startY;
ctx.clearRect(0, 0, canvas.width, canvas.height);
draw();
}
}
function draw() {
ctx.fillRect(rect.startX, rect.startY, rect.w, rect.h);
}
init();
<canvas id="canvas" width="500" height="500"></canvas>
答案 0 :(得分:15)
确保使用某种阈值来检查角落的拖动,使用closeEnough
变量来保持此阈值,然后通过查看角点和鼠标点之间的差异的绝对值来检查角点低于门槛。除此之外,还有很多案例要经历。 Here is a jsFiddle of it
var canvas = document.getElementById('canvas'),
ctx = canvas.getContext('2d'),
rect = {},
drag = false,
mouseX,
mouseY,
closeEnough = 10,
dragTL=dragBL=dragTR=dragBR=false;
function init() {
canvas.addEventListener('mousedown', mouseDown, false);
canvas.addEventListener('mouseup', mouseUp, false);
canvas.addEventListener('mousemove', mouseMove, false);
}
function mouseDown(e) {
mouseX = e.pageX - this.offsetLeft;
mouseY = e.pageY - this.offsetTop;
// if there isn't a rect yet
if(rect.w === undefined){
rect.startX = mouseY;
rect.startY = mouseX;
dragBR = true;
}
// if there is, check which corner
// (if any) was clicked
//
// 4 cases:
// 1. top left
else if( checkCloseEnough(mouseX, rect.startX) && checkCloseEnough(mouseY, rect.startY) ){
dragTL = true;
}
// 2. top right
else if( checkCloseEnough(mouseX, rect.startX+rect.w) && checkCloseEnough(mouseY, rect.startY) ){
dragTR = true;
}
// 3. bottom left
else if( checkCloseEnough(mouseX, rect.startX) && checkCloseEnough(mouseY, rect.startY+rect.h) ){
dragBL = true;
}
// 4. bottom right
else if( checkCloseEnough(mouseX, rect.startX+rect.w) && checkCloseEnough(mouseY, rect.startY+rect.h) ){
dragBR = true;
}
// (5.) none of them
else {
// handle not resizing
}
ctx.clearRect(0,0,canvas.width,canvas.height);
draw();
}
function checkCloseEnough(p1, p2){
return Math.abs(p1-p2)<closeEnough;
}
function mouseUp() {
dragTL = dragTR = dragBL = dragBR = false;
}
function mouseMove(e) {
mouseX = e.pageX - this.offsetLeft;
mouseY = e.pageY - this.offsetTop;
if(dragTL){
rect.w += rect.startX-mouseX;
rect.h += rect.startY-mouseY;
rect.startX = mouseX;
rect.startY = mouseY;
} else if(dragTR) {
rect.w = Math.abs(rect.startX-mouseX);
rect.h += rect.startY-mouseY;
rect.startY = mouseY;
} else if(dragBL) {
rect.w += rect.startX-mouseX;
rect.h = Math.abs(rect.startY-mouseY);
rect.startX = mouseX;
} else if(dragBR) {
rect.w = Math.abs(rect.startX-mouseX);
rect.h = Math.abs(rect.startY-mouseY);
}
ctx.clearRect(0,0,canvas.width,canvas.height);
draw();
}
function draw() {
ctx.fillRect(rect.startX, rect.startY, rect.w, rect.h);
}
init();
答案 1 :(得分:9)
执行一个句柄系统:当鼠标移动时,获取到每个角落的距离以获得光标附近的第一个角色,然后保存它并根据它调整矩形大小。
这是一个说明它的JSfiddle:http://jsfiddle.net/BaliBalo/9HXMG/
function getHandle(mouse) {
if (dist(mouse, point(rect.x, rect.y)) <= handlesSize) return 'topleft';
if (dist(mouse, point(rect.x + rect.w, rect.y)) <= handlesSize) return 'topright';
if (dist(mouse, point(rect.x, rect.y + rect.h)) <= handlesSize) return 'bottomleft';
if (dist(mouse, point(rect.x + rect.w, rect.y + rect.h)) <= handlesSize) return 'bottomright';
if (dist(mouse, point(rect.x + rect.w / 2, rect.y)) <= handlesSize) return 'top';
if (dist(mouse, point(rect.x, rect.y + rect.h / 2)) <= handlesSize) return 'left';
if (dist(mouse, point(rect.x + rect.w / 2, rect.y + rect.h)) <= handlesSize) return 'bottom';
if (dist(mouse, point(rect.x + rect.w, rect.y + rect.h / 2)) <= handlesSize) return 'right';
return false;
}