将数据从jquery ajax传递给grails控制器

Question

我目前有一个拥有此代码的jqgrid，直到我将数据传递到ajax帖子时才会运行

$("#getSelected").click(function(){
                var ids = grid.jqGrid('getGridParam','selarrrow');
                if (ids.length>0) {
                    var names = [];
                    for (var i=0, il=ids.length; i < il; i++) {
                        var name = grid.jqGrid('getCell', ids[i], 'Name');
                        names.push(name);
                    }
                    //alert ("Names: " + names.join(", ") + "; ids: " + ids.join(", "));                
                    $("#names").html(names.join(", "));
                    $("#dialog-confirm").dialog({
                        height:280,
                        modal:true,
                        buttons:{
                            'Cancel': function(){
                                $(this).dialog('close');
                            },
                            'Confirm': function(){
                    //            alert("Confirm");
                                //alert ("Names: " + names.join(", ") + "; ids: " + ids.join(", "));
                                $.ajax({
                                 type: "POST",
                                 url:  "/MyController/downloadFile/",
                                 data: { method: "downloadFile",
                                 orderNum: JSON.stringify(ids),
                                 names: JSON.stringify(names)
                                 },
                                 dataType: "json",
                                 success: function(msg){
                                 alert(msg);
                                 },
                                 error: function(res, status, exception) {
                                 alert(res);
                                 }
                                 });
                            }
                        }
                    });
                }
            });

然后我想发布数据并在我的控制器方法中获取它。控制器方法是downloadFile，我想要它做的就是将所有名称写入文件。这是我目前工作的downloadFile版本

def downloadFile =
{
    def date = new Date()
    SimpleDateFormat sdf = new SimpleDateFormat("MMddyyyy")
    File file = File.createTempFile("MyData",".txt")
    file.write("hello world!")
    String MyTitle = "ChangeMe" + sdf.format(date).toString()
    response.setHeader "Content-disposition", "attachment; filename=${MyTitle}"
    response.contentType = 'text-plain'
    response.outputStream << file.text
    response.outputStream.flush()
}

有什么想法？感谢