Question

抱歉笨拙的问题，我不太确定它是否可能，我用json正确地从Mysql db中读取数据并将它们显示为非表格的元素在数据库中我有一些约会日期，将每周显示给客户组，并有下一个链接到其他一周。有一些代码，我很抱歉。这是HTML代码：

<div class="timesviewport">
    <div class="selector">
        <div class="title-collection" style="">
           <!--time add here-->
        </div>
        <div class="selector-header">
            <div class="header-title-collection" style="">
              <!--date add here--> 
            </div>
            <div class="control">
                <div class="prevlink">
                   <div class="nextprevloading"></div>
                       <a class="prevweeklink" href="#" rel="nofollow">before</a>
                </div>
                <div class="nextlink">
                   <div class="nextprevloading"></div>
                       <a class="nextweeklink" href="#" rel="nofollow" data-test="search-next-week-link">next</a>
                </div>
            </div>
        </div>                                    
    </div>
</div>

这里是javascript

function getresDetails(id)
{
    var new_res_date = '' ;
    var new_res_time = '' ;

    new_res_time += '<div class="title"><div class="title-row-collection">';

    daily = ["Saturday", "Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday"];
    j=0;

    var id_val = id.value;
    var url = "table.php?id="+id_val;

    $.getJSON(url, function(json) {
        new_res_date +='<div class="header-title"><div class="header-title-date-collection" id="adddate">';
        new_res_time += '<div class="title-row"><div class="title-row-date-collection">' ;

        $.each(json, function(i, value) {
            if(i==0)
            {
                new_res_date += '<div class="header-title-date"><div class="header-title-date-name">'+daily[j%7]+ '</div><div class="header-title-date-value">'+json[i].res_date+ '</div></div>';
                new_res_time +=  '<div class="title-row-date"><div class="appointment-collection"><div class="appointment-collection-first"><div><a class="appointment-time" href="#">'+json[i].res_time+'</a></div>' ;
                //alert("first :" +i);
                j++;
            }
            else if (i>0 && json[i-1].res_date==json[i].res_date)
            {
                new_res_time += '<div><a class="appointment-time" href="#">'+json[i].res_time+ '</a></div>';
                //alert("second :" +i);
            }
            else
            {
                new_res_date +=  '<div class="header-title-date"><div class="header-title-date-name">'+daily[j%7]+ '</div><div class="header-title-date-value">'+json[i].res_date+ '</div></div>';
                new_res_time +=  '</div></div></div><div class="title-row-date"><div class="appointment-collection"><div class="appointment-collection-first"><div><a class="appointment-time" href="#">'+json[i].res_time+ '</a></div>';
                //alert("third :" +i);
                j++;
            }
        });
        j=0;
        new_res_date += '</div></div>' ;
        new_res_time += '</div></div></div></div></div></div></div>' ;

        $(new_res_time).appendTo(".title-row-collection");
        $(new_res_date).appendTo(".header-title-collection");
    });
}

和从数据库读取数据的其他页面在这里

table.php：

<?php

include 'configure.php';

$doc_id = $_GET["id"];

$qr = "SELECT `res_date`,`res_time` FROM `reserve_tbl` WHERE `doc_id` = '".$doc_id."'";

$res= mysql_query($qr);


$i=0;

while($row = mysql_fetch_array($res))
{
    $res_arr[$i]["res_date"] = $row["res_date"]; 
    $res_arr[$i]["res_time"] = $row["res_time"];
    $i++;
}

header('Content-type: application/json');
echo json_encode($res_arr);
?>

和 profinf.php：

<?php

include 'configure.php';

$doc_id = $_GET["id"];

$qr = "SELECT * FROM `doc_tbl`  WHERE `doc_id`  = '".$doc_id."'";

$res= mysql_query($qr)  or die("Error: " . mysql_error() . "<br />In Query: " . $qr);;
$i=0;
while($row = mysql_fetch_array($res))
{
    $doc_arr[$i]["doc_name"] = $row["doc_name"];
    $doc_arr[$i]["doc_family"] = $row["doc_family"];
    $doc_arr[$i]["doc_grade"] = $row["doc_grade"];
    $doc_arr[$i]["doc_specialy"]= $row["doc_specialy"];
    $doc_arr[$i]["doc_adress"] = $row["doc_adress"];
    $i++;
}
header('Content-type: application/json');
echo json_encode($doc_arr);
?>

最后这里是连接configure.php

<?php
$cfg_server = "localhost";
$cfg_database   = "db_name";
$cfg_username   = "root";
$cfg_password   = "";

$conn = mysql_connect($cfg_server, $cfg_username, $cfg_password);
if($conn)
{
    if (!mysql_select_db($cfg_database))
    {
        die('Could not select Database: '.mysql_error());
    }
}
if (!$conn)
{
    die('Could not connect to Database: '.mysql_error());
}
?>

以前有人有同样的问题吗？我需要按每周元素显示日期列组，而不是表，如果我使用表更容易？但我不知道如何在表格中显示列周列组！我可以通过SQL查询按数据分组吗？

感谢。

Answer 1

mySql有一个周功能。

如果您将查询更改为： -

SELECT `res_date`,`res_time`, WEEK(res_date) AS `res_week` FROM `reserve_tbl` WHERE `doc_id` = '".$doc_id."'";

您可以使用res_week字段按周编号跟踪每条记录，从而显示上周和下周

json中每日标题栏的标题

1 个答案: