我想在mongodb中为每个集合使用多个模式,如何使用它....?
当我尝试运行它时,它给了我这个错误:
错误:
OverwriteModelError:编译后无法覆盖
allUsers
模型。
OverwriteModelError:编译后无法覆盖checkInOut
模型。
左下我的schema.js
var mongoose = require('mongoose');
var Schema = mongoose.Schema
, ObjectId = Schema.ObjectId;
var checkInInfoSchema= new Schema({
name:String,
loginSerialId:Number
});
var loginUserSchema = new Schema({
sn : { type: Number, unique:true }
,uname: {type:String, unique:true}
,pass:String
});
var registerUserSchema = new Schema({
sn : { type: Number, unique:true }
, name: String //his/her name
,pass:String,
companyKey:{type:String},
uname:{type:String,unique:true}
});
var checkInOutSchema = new Schema({
uname: String
,companyKey:String
,task:String
,inTime:String
,outTime:String
,date:{type:String}
,serialId:{type:Number,unique:true}
,online:Boolean
});
//Different schema for same collection "allUsers"
var allUser=mongoose.model('allUsers',loginUserSchema);
var registerUser=mongoose.model('allUsers',registerUserSchema);
//Different schema for same collection "checkInOut"
var checkInOut=mongoose.model('checkInOut',checkInOutSchema);
var checkInInfo=mongoose.model('checkInOut',checkInInfoSchema);
module.exports={
allUser:allUser,
registerUser:registerUser,
checkInOut:checkInOut,
checkInInfo:checkInInfo
};
答案 0 :(得分:49)
在猫鼬中你可以这样做:
var users = mongoose.model('User', loginUserSchema, 'users');
var registerUser = mongoose.model('Registered', registerUserSchema, 'users');
这两个模式将保存在'用户'集合中。
有关详细信息,请参阅文档:http://mongoosejs.com/docs/api.html#index_Mongoose-model,或者您可以看到以下gist可能会有所帮助。
答案 1 :(得分:2)
我尝试了所选答案,但在查询特定模型对象时,它会检索两个模式的数据。所以我认为使用鉴别器会产生更好的解决方案:
const coordinateSchema = new Schema({
lat: String,
longt: String,
name: String
}, {collection: 'WeatherCollection'});
const windSchema = new Schema({
windGust: String,
windDirection: String,
windSpeed: String
}, {collection: 'WeatherCollection'});
//Then define discriminator field for schemas:
const baseOptions = {
discriminatorKey: '__type',
collection: 'WeatherCollection'
};
//Define base model, then define other model objects based on this model:
const Base = mongoose.model('Base', new Schema({}, baseOptions));
const CoordinateModel = Base.discriminator('CoordinateModel', coordinateSchema);
const WindModel = Base.discriminator('WindModel', windSchema);
//Query normally and you get result of specific schema you are querying:
mongoose.model('CoordinateModel').find({}).then((a)=>console.log(a));
示例输出:
{ __type: 'CoordinateModel', // discriminator field
_id: 5adddf0367742840b00990f8,
lat: '40',
longt: '20',
name: 'coordsOfHome',
__v: 0 },