我似乎无法在本地主机下运行此代码,我的目标是制作一个应该在网站上显示的表但是当我尝试连接时我得到错误:
警告:mysql_connect():在C:\ xampp \ htdocs \ PhpProject2 \ hent.php上 第5行无法连接
my site name: http://localhost/PhpProject2/hent.php
代码:
<html>
<body>
<?php
mysql_connect('<server is here>','<my username here>','<password here>')
or die('can not connect' );
mysql_select_db('<my username here>') or die ('can not connect to <username here>');
$sql = "Select * from Customer";
$result = mysql_query($sql);
$number= mysql_num_rows($result);
for($i=0; $i < $number; $i++)
{
$table = mysql_fetch_row($result);
echo $table[0], $table[1];
echo '<br>';
}
?>
</body>
</html>
我正在使用xampp,MySQL正在端口3306上运行:]
而不是我的&lt;这里的用户名&gt;,&lt;服务器在这里&gt;,&lt;密码在这里&gt;有真实的代码:]
我会感谢任何答案:]
答案 0 :(得分:1)
您可以通过以下方式查看错误:
mysql_connect('<server is here>','<my username here>','<password here>')
or die('Error: '.mysql_error() );
尽量避免使用以mysql_*
开头的所有函数。他们目前正在被剥夺。
使用mysqli或pdo
答案 1 :(得分:1)
试试这个:
<?php
$host = "hostname";
$user = "username";
$password = "password";
$database = "database";
$link = mysqli_connect($host, $user, $password, $database);
If (!$link){
echo ("Unable to connect to database!");
}
else {
$query = "SELECT * FROM Customer";
$result = mysqli_query($link,$query);
while ($row = mysqli_fetch_array($result, MYSQLI_BOTH)){
echo $row['<insert column name>']. "<br>";
}
}
mysqli_close($link);
?>
我在此代码中使用了MYSQL库。您应该检查mysql中的列是否被称为0和1. B.T.W.我正在使用WHILE而不是FOR循环,这只是个人偏好。
答案 2 :(得分:0)
我建议你开始使用PDO;
<强>的index.php 强>
<?php
require "dbc.php";
$getList = $db->getAllData(25);
foreach ($getList as $key=> $row) {
echo $row['columnName'] .' key: '. $key;
}
?>
<强> dbc.php 强>
<?php
class dbc {
public $dbserver = 'server';
public $dbusername = 'user';
public $dbpassword = 'pass';
public $dbname = 'db';
function openDb() {
try {
$db = new PDO('mysql:host=' . $this->dbserver . ';dbname=' . $this->dbname . ';charset=utf8', '' . $this->dbusername . '', '' . $this->dbpassword . '');
} catch (PDOException $e) {
die("error, please try again " . $e);
}
return $db;
}
function getAllData($qty) {
//prepared query to prevent SQL injections
$query = "Select * from Customer where zip= ?";
$stmt = $this->openDb()->prepare($query);
$stmt->bindValue(1, $qty, PDO::PARAM_INT);
$stmt->execute();
$rows = $stmt->fetchAll(PDO::FETCH_ASSOC);
return $rows;
}
?>
答案 3 :(得分:0)
这就是我通常连接到MySQL数据库的方式。 我有config.php
<?php
function db_connect(){
$conn = new mysqli('localhost', 'root', 'leave_black_if_no_password_set', 'database_name');
if (!$conn) {
return false;
}
$conn->autocommit(TRUE);
return $conn;
}
?>
//结束配置
现在,在你的另一个文件中只需调用config.php:`include'config.php';
<html>
<body>
<?php
include 'php/config.php';
$dbCon = db_connect();
$sql = "Select * from Customer";
$result = mysqli_query($dbCon, $sql);
$number= mysqli_num_rows($result);
while($row=mysqli_fetch_array($result)){
{
echo $row['column_name'];
echo '<br>';
}
//close conn
mysqli_close($dbCon);
?>
</body>
</html>