Question

所以我有这个列表和变量：

nums = [14, 8, 9, 16, 3, 11, 5]

big = nums[0]

spot = 0

我对如何实际操作感到困惑。请帮忙！我是Python新手，我想用这个练习给我一个启动器。我想从Scratch或BYOB中的“重复列表长度”开始，但是我如何在Python上做到这一点？

Answer 1

通常，你可以使用

max(nums)

如果您明确要使用循环，请尝试：

max_value = None
for n in nums:
    if n > max_value: max_value = n

Answer 2

nums = [14, 8, 9, 16, 3, 11, 5]

big = None

spot = None

for i, v in enumerate(nums):
    if big is None or v > big:
         big = v
         spot = i

Answer 3

你去......

nums = [14, 8, 9, 16, 3, 11, 5]

big = max(nums)
spot = nums.index(big)

这将是Pythonic实现这一目标的方式。如果要使用循环，则使用当前最大值循环并检查每个元素是否更大，如果是，则分配给当前最大值。

Answer 4

为什么不简单地使用内置的max()函数：

>>> m = max(nums)

顺便说一下，对类似问题的一些答案可能有用：

Answer 5

要解决第二个问题，您可以使用for循环：

for i in range(len(list)):
    # do whatever

您应该注意range()可以包含3个参数：start，end和step。 Start是开头的数字（如果没有提供，则为0）;开始是包容的..结束是在哪里结束（这必须给予）;结束是独家的：如果你做range(100)，它会给你0-99。步骤也是可选的，它表示使用的间隔。如果未提供步骤，则为1.例如：

>>> x = range(10, 100, 5) # start at 10, end at 101, and use an interval of 5
>>> x
[10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95] # note that it does not hit 100

由于end是独占的，要包括100，我们可以这样做：

>>> x = range(10, 101, 5) # start at 10, end at 101, and use an interval of 5
>>> x
[10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100] # note that it does hit 100

Answer 6

Python已经内置了这种要求的功能。

list = [3,8,2,9]
max_number = max(list)
print max_number # it will print 9 as big number

但是如果你找到经典视频的最大数字，你可以使用循环。

list = [3,8,2,9]

current_max_number = list[0]
for number in list:
    if number>current_max_number:
        current_max_number = number

print current_max_number #it will display 9 as big number

Answer 7

scores = [12, 13, 14, 15, 16, 17, 18, 19, 21, 22, 23, 24, 25, 26, 27,
          28, 29, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 31, 31, 37,
          56, 75, 23, 565]

# initialize highest to zero
highest = 0

for mark in scores:
    if highest < mark:
        highest = mark

print(mark)

Answer 8

对于Max in List Code HS，我设法使用此代码让大多数自动平地机为我工作：

list = [-3,-8,-2,0]

current_max_number = list[0]
for number in list:
    if number>current_max_number:
        current_max_number = number

print current_max_number

def max_int_in_list():
    print "Here"

我不确定max_int_in_list的去向。它需要精确地有1个参数。

Answer 9

要打印列表中编号最大的索引。

numbers = [1,2,3,4,5,6,9]

N = 0
for num in range(len(numbers)) :
  if numbers[num] > N :
    N = numbers[num]
print(numbers.index(N))

Answer 10

student_scores[1,2,3,4,5,6,7,8,9]

max=student_scores[0]
for n in range(0,len(student_scores)):
  if student_scores[n]>=max:
    max=student_scores[n]
print(max)
# using for loop to go through all items in the list and assign the biggest value to a variable, which was defined as max.

min=student_scores[0]
for n in range(0,len(student_scores)):
  if student_scores[n]<=min:
    min=student_scores[n]
print(min)
# using for loop to go through all items in the list and assign the smallest value to a variable, which was defined as min.

注意：上面的代码是通过使用for循环来选取最大值和最小值的，这也可以在其他编程语言中使用。但是，max（）和min（）函数是在Python中获得相同结果的最简单方法。

使用循环查找列表中的最大数字

10 个答案: