Question

根据以下代码：

char Secgrp = 0;
    try{
        String a = (String) comboName.getSelectedItem();
        String fill = "Select recDate, attendant, grp from log order by id DESC";
        ps = conn.prepareStatement(fill);
        rs = ps.executeQuery();

        String x = cDate();
        while (rs.next()){

            java.sql.Date dDate = rs.getDate("recDate");
            String bName = rs.getString("attendant");
            char[] cbuf = new char[1];
            rs.getCharacterStream("grp").read(cbuf);
            char theValue = cbuf[0];
            String grp = Character.toString(theValue);


            if(x.equals(dDate.toString()) && group1 == theValue && a.equals(bName)){
               Secgrp = theValue++ ;
            } 
          else if(x.equals(dDate.toString()) && theValue > group1 && a.equals(bName))  
            { Secgrp = theValue++;
            }
            else if(x.equals(dDate.toString()) && group1 > theValue && a.equals(bName))           
           { Secgrp = group1;
            }

根据上面的代码，我正在尝试检查char是否等于我的结果集记录。例如如果A等于A，如果date = date和name = name，则执行某些操作。

但是当我使用setText（String.valueOf（Secgrp））时，没有插入char。

请告知如何从resultSet中检索char，例如'A'。

Answer 1

解决方案：在每个块之后添加中断

       if(x.equals(dDate.toString()) && group1 == theValue && a.equals(bName)){
           Secgrp = theValue++ ;
         Break;
        } 
      else if(x.equals(dDate.toString()) && theValue > group1 && a.equals(bName))  
        { Secgrp = theValue++;
        Break;
        }
        else if(x.equals(dDate.toString()) && group1 > theValue && a.equals(bName))           
       { Secgrp = group1;
         Break;
        }

Java Swing - 从ResultSet获取char

1 个答案: