if else声明

时间:2013-01-21 01:51:01

标签: java android htmlcleaner

我有一些包含多个if / else语句的代码。但是,每当抛出'else'的情况时,所有后续语句也会导致'else'。这是代码,我很感激你的帮助!

public List<Integer> htmlHelper(String arg) throws IOException,
        XPatherException, ParserConfigurationException,
        XPathExpressionException {
    CleanerProperties props = new CleanerProperties();

    props.setTranslateSpecialEntities(true);
    props.setTransResCharsToNCR(true);
    props.setOmitComments(true);

    HtmlCleaner cleaner = new HtmlCleaner(props);
    rootNode = cleaner.clean(arg);


    TagNode tagNode = new HtmlCleaner(props).clean(new URL(
            "http://www.athletics.psu.edu/psustrength/index_rec.asp"));
    org.w3c.dom.Document doc = (org.w3c.dom.Document) new DomSerializer(
            new CleanerProperties()).createDOM(tagNode);

    XPath jpath = XPathFactory.newInstance().newXPath();
    String recinfo = (String) jpath
            .evaluate(

"/html/body/div/div[1]/div/div/table/tbody/tr[3]/td[2]/p[2]/text()",
                    doc, XPathConstants.STRING);
    String recnum = recinfo.replaceAll("\\D+", "");

    if (recnum != null && recnum.length() == 0) {

        recnumint = 500;
        grec = 0;
    } else {
        recnumint = Integer.parseInt(recnum);
        grec = recnumint;
    }

    XPath ipath = XPathFactory.newInstance().newXPath();
    String iminfo = (String) ipath
            .evaluate(

"/html/body/div/div[3]/div/div/table/tbody/tr[2]/td[2]/p[2]/text()",
                    doc, XPathConstants.STRING);
    String imnum = iminfo.replaceAll("\\D+", "");

    if (imnum != null && recnum.length() == 0) {

        imint = 400;
        gim = 0;
    } else {
        imint = Integer.parseInt(imnum);
        gim = imint;
    }

    XPath xpath = XPathFactory.newInstance().newXPath();
    String whiteinfo = (String) xpath
            .evaluate(

"/html/body/div/div[3]/div/div/table/tbody/tr[1]/td[2]/p[2]/text()",
                    doc, XPathConstants.STRING);
    String whitenum = whiteinfo.replaceAll("\\D+", "");

    if (whitenum != null && recnum.length() == 0) {

        whitenumint = 450;
        gwhite = 0;
    } else {
        whitenumint = Integer.parseInt(whitenum);
        gwhite = whitenumint;
    }

    XPath fpath = XPathFactory.newInstance().newXPath();
    String fitinfo = (String) fpath
            .evaluate(

"/html/body/div/div[3]/div/div/table/tbody/tr[4]/td[2]/p[2]/text()",
                    doc, XPathConstants.STRING);
    String fitnum = fitinfo.replaceAll("\\D+", "");

    if (fitnum != null && recnum.length() == 0) {

        fitint = 470;
        gfit = 0;
    } else {
        fitint = Integer.parseInt(fitnum);
        gfit = fitint;
    }



    List<Integer> list = new ArrayList<Integer>();
    list.add(recnumint);
    list.add(whitenumint);
    list.add(imint);
    list.add(fitint);

    return list;
}

}

如前所述,当抛出第一个'else'语句时会出现问题。如果第一种情况是'如果'而第二种情况是'其他',那么第三种情况和第四种情况也将是'其他'

2 个答案:

答案 0 :(得分:2)

你所有的if共享相同的第二个条件,也许这就是原因?

你的意思是

if (imnum != null && imnum .length() == 0) {
                     ^^^^^^

而不是

if (imnum != null && recnum.length() == 0) {

同样

if (whitenum != null && whitenum.length() == 0) {
                        ^^^^^^^^^

当然..

if (fitnum != null && fitnum.length() == 0) {
                      ^^^^^^

答案 1 :(得分:0)

请记住,NOT(A和B)与(NOT A)OR(NOT B)相同。使用调试器找出失败的条件。