所以我有一个非常简单的日历代码,但是我无法弄清楚如何查询mysql数据库以查找每月的每一天的任何事件。我知道如何查询数据库中的信息,但我不知道我会把它放在创建日历的代码或如何构建它或任何东西。香港专业教育学院看了许多PHP日历的代码,并且对于每个代码我都无法从我的数据库中获取数据,我只是不知道该怎么做。任何帮助都很感激,谢谢。 日历代码编辑为包含db stuff:
include ("connection.php");
$date =time ();
$day = date('d', $date);
$month = date('m', $date);
$month = $month + "02";
$year = date('Y', $date);
$years = substr($year, 2, 2);
$first_day = mktime(0,0,0,$month, 1, $year);
$title = date('F', $first_day);
$day_of_week = date('D', $first_day);
switch($day_of_week){
case "Sun": $blank = 0; break;
case "Mon": $blank = 1; break;
case "Tue": $blank = 2; break;
case "Wed": $blank = 3; break;
case "Thu": $blank = 4; break;
case "Fri": $blank = 5; break;
case "Sat": $blank = 6; break;
}
$days_in_month = cal_days_in_month(0, $month, $year);
echo "<table border=1 width=294>";
echo "<tr><th colspan=7> $title $year </th></tr>";
echo "<tr><td width=42>S</td><td width=42>M</td><td
width=42>T</td><td width=42>W</td><td width=42>T</td><td
width=42>F</td><td width=42>S</td></tr>";
$day_count = 1;
echo "<tr>";
while ( $blank > 0 )
{
echo "<td></td>";
$blank = $blank-1;
$day_count++;
}
$day_num = 1;
while ( $day_num <= $days_in_month )
{
echo "<td> $day_num <br/>";
$result = mysql_query("SELECT time, length FROM hire WHERE day = '$day_num' and month = '$month' and year = '$years'") or die ('Error: '.mysql_error ());
while($ row = mysql_fetch_array($ result)){
$time = $row['time'];
$length = $row['length'];
}
if (isset($time) and (isset($length))) {
echo "Time: " . $time . "<br/> Length: " . $length . "<br/>";
}
"</td>";
$day_num++;
$day_count++;
if ($day_count > 7)
{
echo "</tr><tr>";
$day_count = 1;
}
}
while ( $day_count >1 && $day_count <=7 )
{
echo "<td> </td>";
$day_count++;
}
echo "</tr></table>";
答案 0 :(得分:0)
您需要将数据库代码放到输出日期单元格的位置。这是代码:
<?php
include ("connection.php");
$date =time ();
$day = date('d', $date);
$month = date('m', $date);
$month = $month + "01";
$year = date('Y', $date);
$first_day = mktime(0,0,0,$month, 1, $year);
$title = date('F', $first_day);
$day_of_week = date('D', $first_day);
switch($day_of_week){
case "Sun": $blank = 0; break;
case "Mon": $blank = 1; break;
case "Tue": $blank = 2; break;
case "Wed": $blank = 3; break;
case "Thu": $blank = 4; break;
case "Fri": $blank = 5; break;
case "Sat": $blank = 6; break;
}
$days_in_month = cal_days_in_month(0, $month, $year);
echo "<table border=1 width=294>";
echo "<tr><th colspan=7> $title $year </th></tr>";
echo "<tr><td width=42>S</td><td width=42>M</td><td width=42>T</td><td width=42>W</td><td width=42>T</td><td width=42>F</td><td width=42>S</td></tr>";
$day_count = 1;
echo "<tr>";
while ( $blank > 0 )
{
echo "<td></td>";
$blank = $blank-1;
$day_count++;
}
$day_num = 1;
while ( $day_num <= $days_in_month )
{
//database code here
$result = ''; //formatted html result
echo "<td> $day_num $result</td>";
$day_num++;
$day_count++;
if ($day_count > 7)
{
echo "</tr><tr>";
$day_count = 1;
}
}
while ( $day_count >1 && $day_count <=7 )
{
echo "<td> </td>";
$day_count++;
}
echo "</tr></table>";