我无法从CodeIgniter视图中的$ info(如下所述)中检索值。
以下是该方案: 我解释了代码的所有内容。
function info() {
{...} //I retrieve results from database after sending $uid to model.
$dbresults = $this->my_model->get_info($uid); //Assume that this model returns some value.
foreach($dbresults as $row) {
$info = $row->address; //This is what I need to produce the results
$results = $this->my_model->show_info($info);
return $results; //This is my final result which can't be achieved without using $row->address. so first I have to call this in my controller.
}
// Now I want to pass it to a view
$data['info'] = $results;
$this->load->view('my_view', $data);
//In my_view, $info contains many values inherited from $results which I need to call one by one by using foreach. But I can't use $info with foreach because it is an Invalid Parameter as it says in an error.
答案 0 :(得分:3)
在$result
内使用foreach
是不合理的。因为在每个循环中$ result将获取一个新值。因此,最好将其用作array
,然后将其传递给您的视图。此外,您不应在return
内使用foreach
。
function info() {
{...} //I retrieve results from database after sending $uid to model.
$dbresults = $this->my_model->get_info($uid); //Assume that this model returns some value
$result = array();
foreach($dbresults as $row) {
$info = $row->address; //This is what I need to produce the results
$result[] = $this->my_model->show_info($info);
}
// Now I want to pass it to a view
$data['info'] = $result;
$this->load->view('my_view', $data);
}
在var_export($result);
结束后查看$ result数组{1 var_dump($result);
或foreach
。并确保这是您要发送到视图的内容。
现在,在您看来,您可以这样做:
<?php foreach ($info as $something):?>
//process
<?php endforeach;?>
答案 1 :(得分:1)
请从
中删除返回声明foreach($dbresults as $row) {
$info = $row->address; //This is what I need to produce the results
$results[] = $this->my_model->show_info($info);
// return $results; remove this line from here;
}
$data['info'] = $results; // now in view access by $info in foreach
$this->load->view('my_view', $data);
现在可以在视图中访问$ info。
希望这会对你有帮助!