索尼智能手表 - 小部件水龙头上的振动智能手表

时间:2013-01-19 10:17:35

标签: android widget sony sony-smartwatch

我正在尝试开发一个可以轻松发送短信的小部件扩展程序。这很有效,但我想确认通过振动智能手表发送了短信。我可以从小部件扩展程序启动振动器吗?

据我了解,发送主机应用程序的意图应该足以启动振动。

在我的类中扩展WidgetExtension onTouch:

SmsManager sms = SmsManager.getDefault();
sms.sendTextMessage("124124512", null, "blaa", null, null); // Works fine

Intent intent = new Intent(Control.Intents.CONTROL_VIBRATE_INTENT);
intent.putExtra(Control.Intents.EXTRA_ON_DURATION, 1000);
intent.putExtra(Control.Intents.EXTRA_OFF_DURATION, 1000);
intent.putExtra(Control.Intents.EXTRA_REPEATS, 1);
intent.putExtra(Control.Intents.EXTRA_AEA_PACKAGE_NAME, mContext.getPackageName());
intent.setPackage(mHostAppPackageName);
context.sendBroadcast(intent, Registration.HOSTAPP_PERMISSION); // No vibration

我还尝试创建扩展ControlExtension的单独Vibrator类:

public class Vibrator extends ControlExtension{

    public Vibrator(Context context, String hostAppPackageName) {
        super(context, hostAppPackageName);
        // TODO Auto-generated constructor stub
    }

    public void vibrate(){
        startVibrator(1000, 1000, 1);
    }

}

从小部件扩展中触发振动没有任何效果。我忽视的东西?非常感谢!

1 个答案:

答案 0 :(得分:1)

似乎在小部件触摸上启动振动的唯一方法是启动一个sparate ControlExtension:

小工具onTouch:

Intent intent = new Intent(Control.Intents.CONTROL_START_REQUEST_INTENT);
intent.putExtra(Control.Intents.EXTRA_AEA_PACKAGE_NAME, mContext.getPackageName());
sendToHostApp(intent);

在注册信息中:

将getRquiredControlApiVersion设置为返回1.

并在ExtensionService中添加:

@Override
public ControlExtension createControlExtension(String hostAppPackageName) {
    return new Vibrator(hostAppPackageName, this);
}

和振动器类:

public class Vibrator extends ControlExtension{


Vibrator(String hostAppPackageName, Context context){
    super(context, hostAppPackageName); 

}   

 @Override
    public void onStart() {
        vibrate();
        SmsManager sms = SmsManager.getDefault();
        sms.sendTextMessage("123456789", null, "BLAAA", null, null); 
        showBitmap(new SmartWatchSampleWidgetImage(mContext, 2).getBitmap());
    }

 @Override
    public void onTouch(final ControlTouchEvent event) {
        int action = event.getAction();
        if (action == Control.Intents.TOUCH_ACTION_PRESS) {

        }      
 }

public void vibrate(){

     if(hasVibrator()){
            startVibrator(1000, 500, 3);
     }
}
}

这份工作。