Question

我有一个包含此值的表格：

Articles/Search/ArtMID/2681/ArticleID/2218/Diet.aspx
OurStory/MeettheFoodieandtheMD.aspx
TheFood/OurMenu.aspx

我想得到这个

Diet.aspx
MeettheFoodieandtheMD.aspx
OurMenu.aspx

我该怎么做？

Answer 1

在SQL中执行此操作的方法：

SELECT SUBSTRING( string , LEN(string) -  CHARINDEX('/',REVERSE(string)) + 2  , LEN(string)  ) FROM SAMPLE;

JSFiddle here http://sqlfiddle.com/#!3/41ead/11

Answer 2

SELECT REVERSE(LEFT(REVERSE(columnName), CHARINDEX('/', REVERSE(columnName)) - 1))
FROM   tableName

SQLFiddle Demo

ORHER SOURCE（s）

Answer 3

请尝试：

select url,(CASE WHEN CHARINDEX('/', url, 1)=0 THEN url ELSE RIGHT(url, CHARINDEX('/', REVERSE(url)) - 1) END)
from(
    select 'Articles/Search/ArtMID/2681/ArticleID/2218/Diet.aspx' as url union
    select 'OurStory/MeettheFoodieandtheMD.aspx' as url union
    select 'MeettheFoodieandtheMD.aspx' as url
)xx

Answer 4

SELECT REVERSE ((
    SELECT TOP 1 value FROM STRING_SPLIT(REVERSE('Articles/Search/ArtMID/2681/ArticleID/2218/Diet.aspx'), '/')
)) AS fName
Result: Diet.aspx

标准STRING_SPLIT不允许取最后一个值。

诀窍是在用REVERSE分割之前反转字符串（STRING_SPLIT），从末尾获取第一个值（TOP 1 value），然后需要再次反转结果（ REVERSE）恢复原始字符序列。

在使用SQL表时，这是常见的方法：

SELECT REVERSE ((
    SELECT TOP 1 VALUE FROM STRING_SPLIT(REVERSE(mySearchString), '/')
)) AS myLastValue
FROM myTable

Answer 5

请尝试以下代码：

SELECT SUBSTRING( attachment, LEN(attachment) 
     - CHARINDEX('/', REVERSE(attachment)) + 2, LEN(attachment)  ) AS filename 
FROM filestable;

Answer 6

更简单，更优雅：

select reverse(SPLIT_PART(reverse('Articles/Search/ArtMID/2681/ArticleID/2218/Diet.aspx'), '/',1))

Answer 7

我更正了jazzytomato的单字符令牌（Diet.aspx）和单个令牌（SELECT SUBSTRING( string , LEN(string) - CHARINDEX('/','/'+REVERSE(string)) + 2 , LEN(string) ) FROM SAMPLE;）的解决方案

uib-dropdown

Answer 8

尝试一下。更简单。

SELECT RIGHT（字符串，CHARINDEX（'/'，REVERSE（字符串））-1） FROM TableName

Answer 9

Create Table #temp
(
ID int identity(1,1) not null,
value varchar(100) not null
)

DECLARE @fileName VARCHAR(100);

INSERT INTO #temp(value) SELECT value from STRING_SPLIT('C:\Users\Documents\Datavalidation\Input.csv','\')
SET @fileName=(SELECT TOP 1 value from #temp ORDER BY ID DESC);
SELECT @fileName AS File_Name;

DROP TABLE #temp

Answer 10

一种稍微更紧凑的方法（类似于 ktaria 的答案，但在 SQL Server 中）是

SELECT TOP 1 REVERSE(value) FROM STRING_SPLIT(REVERSE(fullPath), '/') AS fileName

Answer 11

PostgreSQL 的等价物：

SELECT reverse(split_part(reverse(column_name), '/', 1));

Answer 12

reverse(SUBSTRING(reverse(yourString),0,CHARINDEX('/',reverse(yourString)))) as stringLastPart

拆分字符串并取最后一个元素

12 个答案: