我需要从ldap查询转换字符串。我正在查询我的Active Directory服务器以获取用户帐户。这是我拉的字符串。
"CN=Phil Robertson,OU=Users,OU=Duck Commander,OU=Department & Buildings,DC=OCSDtest,DC=local"
我希望它转换为一个看起来像这样的数组
$array['local']['OCtest']['Department & Buildings']['Duck Commander']['Users']['Phil Robertson']=1;
不是
$array( [1]=>'local,[2]=>'OCtest',[3]='Depart',[4]='Duck Commander',[5]='Users');
到目前为止我已经
了示例代码---
$dnn2 = ldap_explode_dn("CN=Phil Robertson,OU=Users,OU=Duck Commander,OU=Department & Buildings,DC=OCSDtest,DC=local",1);
unset($dnn2['count']);
echo "<pre>";
print_r(array_reverse($dnn2));
我需要什么?
答案 0 :(得分:1)
试试这个
$arrayvalue = array();
foreach($dnn2 as $dn)
{
$temp = explode('=',$dn);
$temp1 = substr($temp[1], 0, strpos($temp1[1], ','));
$arrayvalue[] = $temp1;
}
print_r($arrayvalue);
答案 1 :(得分:0)
试试这个
$a = array();
foreach($dnn2 as $dn)
{
$arr = explode('=',$dn);
$a[] = $arr[1]; //or $a[] = array($arr[1]); for 6 dimensional array
}
print_r($a);
答案 2 :(得分:0)
$dnn2 = ldap_explode_dn("CN=Phil Robertson,OU=Users,OU=Duck Commander,OU=Department & Buildings,DC=OCSDtest,DC=local",1);
unset($dnn2['count']);
$result = null;
$ref =& $result;
foreach (array_reverse($dnn2) as $dn) {
$ref = array($dn => null);
$ref =& $ref[$dn];
}
print_r($result);